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3 years ago

Crane Company provided the following information from its accounting records for 2019.

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

8 0

Answer:

$10.00 per hour

Step-by-step explanation:

Overhead application rate which is also known as overhead absorption rate on the basis on labor hours is the total budgeted overhead for 2019 which is $900,000 divided by the expected production of 90,000 labor hours for the year.

overhead application rate=$900,000/90,000=$10 per hour

This implies that for every one hour worked overhead cost of $10 would be added to the other costs incurred.

The correct option then is the third option of $10.00 per hour

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Complete the steps to find the value of x.<br> 2x<br> 1289<br> 22<br> 2

Oksanka [162]

Answer:

Step-by-step explanation:

2x = 128

x = 128/2

x = 64

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3 years ago

Any ordered pair that makes all equations in a system of equations true is a(n) ...?

timurjin [86]

That ordered pair is a solution to the equation system.

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4 years ago

Video games are on sale for 25% off. If a particular game regularly sells for $59.50, what is the sale price? a. $34.83 b. $14.8

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3 years ago

A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe

Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

$Volume=\frac{1}{2} (b_{1}+4+2x)h X H$

$Volume=\frac{1}{2} (4+4+2x)h X 16$

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

$V=64h+16h(\frac{h}{4})$

$V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}$

h=3m,

dV/dt=25cm/min=0.25 m/min

$0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}$

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0

3 years ago

Suppose log subscript a x equals 3, log subscript a y equals 7, and log subscript a z equals short dash 2. Find the value of the

enyata [817]

Answer:

Step-by-step explanation:

Given the following logarithmic expressions $log_ax = 3, log_ay = 7, log_az = -2$ , we are to find the value of $log_a(\frac{x^3y}{z^4} )$

$from\ log_ax = 3, x = a^3\\\\from\ log_ay = 7,y = a^7\\\\from\ log_az = -2, z = a^{-2}$ Substituting x = a³, y = a⁷ and z = a⁻² into the log function $log_a(\frac{x^3y}{z^4} )$ we will have;

$= log_a(\frac{x^3y}{z^4} )\\\\= log_a(\dfrac{(a^3)^3*a^7}{(a^{-2})^4} )\\\\= log_a(\dfrac{a^9*a^7}{a^{-8}} )\\\\= log_a\dfrac{a^{16}}{a^{-8}} \\\\= log_aa^{16+8}\\\\= log_aa^{24}\\\\= 24log_aa\\\\= 24* 1\\\\= 24$

Hence, the value of the logarithm expression is 24

6 0

3 years ago