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Romashka-Z-Leto [24]
2 years ago
14

2. A function fis graphed below, which consists of two semicircles and two linear pieces.

Mathematics
1 answer:
ivolga24 [154]2 years ago
8 0
Ist b hope that helps
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If a water tank already contains 55 gallons of water when baxter begins to fill it and water is flowing in at a rate of 8 gallon
saw5 [17]

Answer:

I think it would be 55+8x. I hope this helps. :)

Step-by-step explanation:

55 gallons of water

8 gallons per minute

It would be 55 gallons (the original amount in the tank) plus 8 gallons per minute. (8x)

x = how many minutes the tank is being filled up more.

so if you were to fill up the tank another 5 minutes, the equation would be 55+8(5)

55+40

95 would be the answer.

6 0
3 years ago
I need to know how to multiply 2/9×5/7
lord [1]

Answer: 10/63

Step-by-step explanation: To multiply fractions, you just time's the top numbers and then the bottom numbers by themselves.

For instance: 2 x 5 = 10

                       9 x 7 = 63

and there is your answer.

:)

4 0
2 years ago
How far is 0, 7 from the origin
Delvig [45]

Answer:

7

Step-by-step explanation:

Count the numbers in between (0,0) and (0,7).

5 0
2 years ago
A balloon is rising at a constant speed of 5 ftys. A boy is cycling along a straight road at a speed of 15 ftys. When he passes
Ket [755]

Answer:

  13 ft/s

Step-by-step explanation:

t seconds after the boy passes under the balloon the distance between them is ...

  d = √((15t)² +(45+5t)²) = √(250t² +450t +2025)

The rate of change of d with respect to t is ...

  dd/dt = (500t +450)/(2√(250t² +450t +2025)) = (50t +45)/√(10t² +18t +81)

At t=3, this derivative evaluates to ...

  dd/dt = (50·3 +45)/√(90+54+81) = 195/15 = 13

The distance between the boy and the balloon is increasing at the rate of 13 ft per second.

_____

The boy is moving horizontally at 15 ft/s, so his position relative to the spot under the balloon is 15t feet after t seconds.

The balloon starts at 45 feet above the boy and is moving upward at 5 ft/s, so its vertical distance from the spot under the balloon is 45+5t feet after t seconds.

The straight-line distance between the boy and the balloon is found as the hypotenuse of a right triangle with legs 15t and (45+5t). Using the Pythagorean theorem, that distance is ...

  d = √((15t)² + (45+5t)²)

7 0
2 years ago
This is a picture of a cube and the net for this cube.
Kryger [21]
It’s C 450mm^2 goodluck
6 0
3 years ago
Read 2 more answers
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