Let
x------------><span>Sean vegetable plants
</span>y------------>Liz vegetable plants
z------------>Sejuan vegetable plants
we know that
y=3
z=2
x=3(y+z)--------> 3(3+2)=15
the answer part A) is
Sean has 15 vegetable plants
part B
This is an example of a part-whole problem.----------> true
<span>This is an example of a comparison problem.-------> true
</span>Addition then multiplication can be used to solve the problem.------> true
Answer:
40°
Step-by-step explanation:
- Using corresponding angle rules
If 2 boxes remain empty, it means that we put all three balls in one single box.
Suppose the full box is box number 1. For each ball, we have three choices - we may put it in box number 1, 2 or 3. This means that each box has a 1/3 chance of receiving each ball.
So:
- we choose box 1 for ball 1 - that's a 1/3 chance
- we choose box 1 for ball 2 - that's a 1/3 chance
- we choose box 1 for ball 3 - that's a 1/3 chance
So, the probability of putting all balls in box 1 is
But this is the probability of putting all ballx in box 1, and you can repeat this logic for box 2 and 3.
So, the probability of putting all balls in one single box is 1/27 for each box, for a total of
One solution x = 1, y = 4