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AURORKA [14]
3 years ago
13

Can someone please help me?:(

Mathematics
1 answer:
Leto [7]3 years ago
3 0

9514 1404 393

Answer:

  • parallelogram: 80 mm²
  • triangle: 40 mm²

Step-by-step explanation:

The formula for the area of a parallelogram is ...

  A = bh

Here, the base is 8 mm and the height (perpendicular to the base) is 10 mm. Then the area is ...

  A = (8 mm)(10 mm) = 80 mm² . . . . area of the parallelogram

__

As you can see from the problem setup, the area of the triangle is exactly half that: 80 mm²/2 = 40 mm² . . . . area of the triangle

_____

If you'd rather use the formula for the triangle area, you will see that you get the same result:

  A = (1/2)bh

  A = (1/2)(8 mm)(10 mm) = 1/2·80 mm² = 40 mm² . . . . area of the triangle

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Step-by-step explanation:

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3 years ago
Read 2 more answers
Do you think the equations (x−1)(x+3)=17+x and (x−1)(x+3)+500=517+x should have the same solution set? Why?
oksano4ka [1.4K]

Answer:

Those two pair of equations have the same solution set.

Step-by-step explanation:

There are two equations  

(x-1)(x+3)=17+x ..... (1) and  

(x-1)(x+3)+500=517+x ...... (2)

We have to check the same solution set will be there for equations (1) and (2) or not.

Now, we are going to rearrange the equation (2).

(x-1)(x+3)+500=517+x

⇒ (x-1)(x+3)=517-500+x

⇒(x-1)(x+3)=17+x

This is the same equation as equation (1).  

Therefore, there will be the same solution set for equations (1) and (2).  (Answer)

There are two equations  

(x-1)(x+3)=17+x ..... (3) and  

3(x-1)(x+3)+500=51+3x ...... (4)

We have to check the same solution set will be there for equations (3) and (4) or not.

Now, we are going to rearrange the equation (4).

3(x-1)(x+3)+500=51+3x

⇒ 3(x-1)(x+3)=3(17+x)

⇒(x-1)(x+3)=17+x

This is the same equation as equation (3).  

Therefore, there will be the same solution set for equations (3) and (4). (Answer)

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3 years ago
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Answer:

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Step-by-step explanation:

When there are 2 neatives together like that it changes to a positive. So it woud be 329+104=433

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