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aalyn [17]
3 years ago
13

Consider the equation ay'' + by' + cy = d, where a, b, c, and d are constants. (a) find all equilibrium, or constant, solutions

of this differential equation. (enter your answers as a comma-separated list of equations.)
Mathematics
1 answer:
Orlov [11]3 years ago
4 0
Rewrite equation so that it is homogeneous . 
ay'' +by' + cy = 0

Solve characteristic equation:
ar^2 +br + c = 0 \\ \\ r = \frac{(-b) \pm \sqrt{b^2 -4ac}}{2a} 

The solutions to the homogeneous equation are:
y = k_1 e^{r_1 t} + k_2 e^{r_2 t}

Finally you need the constant term in "cy" to equal 'd' to satisfy the particular solution.
y= k_1 e^{r_1 t} + k_2 e^{r_2 t} + \frac{d}{c}
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P(5) = 1/8

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Pilar ha comprado un coche, da una entrada y lo quiere pagar en 12 meses. Cada mes va a pagar 600,82€. Si ha dado al principio u
Molodets [167]

Answer:

Pilar va a pagar en total por el coche 14209.84€.

Step-by-step explanation:

Pilar ha comprado un coche, da una entrada y lo quiere pagar en 12 meses.

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7 0
3 years ago
Write an expression for the eighth partial sum of the series using summation notation
balandron [24]

Answer:

option B

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9/10 + 6/5 + 3/2...........

We find the difference between the terms

\frac{6}{5} - \frac{9}{10}

\frac{12}{10} - \frac{9}{10} = \frac{3}{10}

We will get the same difference when we subtract consecutive terms.

so , d= 3/10, a= 9/10

we find the formula for nth term

a_n = a+(n-1) d

a_n = \frac{9}{10} + (n-1)\frac{3}{10}

a_n = \frac{9}{10} +\frac{3}{10}n-\frac{3}{10}

a_n = \frac{6}{10} +\frac{3}{10}n

a_n = \frac{3}{5} +\frac{3}{10}n

we need to find eighth partial sum so we  take n=1 to 8

sum of 8 terms (\frac{3}{5} +\frac{3}{10}n)

So option B is correct


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