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aalyn [17]
3 years ago
13

Consider the equation ay'' + by' + cy = d, where a, b, c, and d are constants. (a) find all equilibrium, or constant, solutions

of this differential equation. (enter your answers as a comma-separated list of equations.)
Mathematics
1 answer:
Orlov [11]3 years ago
4 0
Rewrite equation so that it is homogeneous . 
ay'' +by' + cy = 0

Solve characteristic equation:
ar^2 +br + c = 0 \\ \\ r = \frac{(-b) \pm \sqrt{b^2 -4ac}}{2a} 

The solutions to the homogeneous equation are:
y = k_1 e^{r_1 t} + k_2 e^{r_2 t}

Finally you need the constant term in "cy" to equal 'd' to satisfy the particular solution.
y= k_1 e^{r_1 t} + k_2 e^{r_2 t} + \frac{d}{c}
You might be interested in
Please help, this chapter was on derivatives...
Usimov [2.4K]
<h3>Answer:  ds/dt = 11</h3>

================================================

Work Shown:

Before we can use derivatives, we need to find the value of s when (x,y) = (15,20)

s^2 = x^2+y^2

s^2 = 15^2+20^2

s^2 = 225+400

s^2 = 625

s = sqrt(625)

s = 25

-----------

Now we can apply the derivative to both sides to get the following.  Don't forget to use the chain rule.

s^2 = x^2 + y^2

d/dt[s^2] = d/dt[x^2 + y^2]

d/dt[s^2] = d/dt[x^2] + d/dt[y^2]

2s*ds/dt = 2x*dx/dt + 2y*dy/dt

2(25)*ds/dt = 2(15)*5 + 2(20)*(10)

50*ds/dt = 150 + 400

50*ds/dt = 550

ds/dt = 550/50

ds/dt = 11

-----------

Side note: The information t = 40 is never used. It's just extra info.

8 0
2 years ago
Mr. Heath organizes a six-game tournament where players will
EleoNora [17]

9514 1404 393

Answer:

  (W, T, L, S) = (3, 2, 1, 4.1)

Step-by-step explanation:

For some number of wins (W), ties (T), and losses (L), the player's score will be ...

  score = 2.2W +0.25T -3L

For 3 wins, 2 ties, and 1 loss, the player's score is ...

  2.2(3) +0.25(2) -3(1) = 6.6 +0.5 -3 = 4.1

4 0
2 years ago
(3d^4)^2<br><br><br> In index form
enyata [817]

Answer:

9d^8

Step-by-step explanation:

i think

8 0
3 years ago
Six bags of Takis costs $13.50. Five bags of Takis costs $10. Which has
viktelen [127]

Answer:

the correct answer is 5 bags

4 0
2 years ago
Read 2 more answers
Using the image above, if the density of the LEGO piece is 0.85 g/cm^3, what COULD be a possible measurement for the density of
grin007 [14]

The Lego is submerged under the oil and therefore, is more dense than the oil

The possible density of the oil is the option;

<u>0.79 g/cm³</u>

Reason:

Given:

The density of Lego = 0.85 g/cm³

Density of oil = Required

Solution:

The density of an object is the mass per unit volume it occupies

  • Density = \dfrac{Mass}{Volume}

Increase in density increases the mass a unit volume occupies, therefore, a

more dense object is heavier than a less dense object such that the less

dense object will float on a dense object

The oil is floating on the Lego, therefore, the Lego is more dense than the

oil, and we have;

  • Density of Lego > Density of oil

The density of Lego = 0.85 g/cm³

Therefore;

0.85 g/cm³ > Density of oil

From the given options, the option that has a density less than 0.85 g/cm³ is the the option 0.79 g/cm³

Therefore, the possible density of the oil is <u>0.79 g/cm³</u>

<u />

Learn more here:

brainly.com/question/12864420

6 0
2 years ago
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