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Alenkasestr [34]
3 years ago
14

Please help needed and thank you

Mathematics
1 answer:
rodikova [14]3 years ago
4 0
17. 9
18. 12
19. 16
20. 56
21. 143
22. 14
23. 27
24. 7

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i can help, but you need to write the whole question..

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A perfect square trinomial can be represented by a square model with equivalent length and width. Which polynomial can be repres
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The correct answer is 
A) x^2 - 6x + 9

In fact, this is a trinomial of the form ax^2-bx+c, whose solutions are given by
x_{1,2}=  \frac{-b\pm \sqrt{b^2 -4ac} }{2a}
Using this formula for the trinomial of the problem, we find:
x1,2=  \frac{6 \pm \sqrt{6^2-4\cdot 1\cdot 9}}{2} =3
<span>we see that this trinomial has two coincident solutions (x=3 with multiplicity 2). This means that it can be rewritten as a perfect square, in the following form: 
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3 years ago
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Yolanda closed on a 20 year home loan for $83,000. she chooses to buy only 1 point at closing. by buying a point at her closing,
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The correct answer is B) 11 years
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Which is f(-3) for the quadratic function graphed?<br> -9<br> -3<br> 0<br> 9
KATRIN_1 [288]

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9

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20. Based on student records, 25% of the students at a large high school have a
Elenna [48]

Answer:

(E) 0.71

Step-by-step explanation:

Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.

So, the  probability that the student has a GPA lower than 3.5 and is not taking any AP  classes is calculated as:

P(A'∩B') = 1 - P(A∪B)

it means that the students that have a GPA lower than 3.5 and are not taking any AP  classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.

Therefore, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled  in at least one AP class is 0.12

So, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(A∪B) = 0.25 + 0.16 - 0.12

P(A∪B) = 0.29

Finally, P(A'∩B') is equal to:

P(A'∩B') = 1 - P(A∪B)

P(A'∩B') = 1 - 0.29

P(A'∩B') = 0.71

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3 years ago
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