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3 years ago

Solve -0.4k - 6 = 1.2. Explain your answer.

Mathematics

1 answer:

jeka57 [31]3 years ago

7 0

Answer:

k=-18

Step-by-step explanation:

To solve this, we need to isolate the variable k.

-0.4k-6=1.2

We can add 6 to both sides first.

-0.4k=7.2

Recall that what you do to one side of an equation you have to do to the other side too, so the equation remains equal.

Next, we can divide both sides by -0.4

k=-18

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To use distributive property solve equation 2(a+3)=-12

WARRIOR [948]

Answer: a= -18/2

Step-by-step explanation:

2a + 2x3 = -12

2a + 6 = -12

2a + 6 - 6 = -12 - 6 ( subtract 6 from both sides)

2a = -18 (Divide 2 by both sides)

a= -18/2

4 0

3 years ago

Select the property of equality used to arrive at the conclusion.

Naya [18.7K]

Answer:

addition property of equality

Step-by-step explanation:

This is because the addition property of equality means

if $a=b$ then $a+c=b+c$

So if, $x=2$ then $x+8=2+8$

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2 years ago

144 divide by 24 show your work

Virty [35]

If you want to show your work, you would need to do the problem yourself.
144/24 is 6

6 0

3 years ago

Read 2 more answers

Help me solve this ok..

oksian1 [2.3K]

3x+3x-5= 1

6x-5=1

Whenever moving a number, the sign always changes.

6x-5+5= 1+5

6x= 1+5

6x= 6

divide both sides by 6

6x/6= 6/6

x= 1

Check solution by using the substitution method

3(1)+3(1)-5=1

3+3-5=1

6-5= 1

1=1

Answer: x=1

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3 years ago

Read 2 more answers

We often deal with weighted means, in which different data values carry different weights in the calculation of the mean. For

Veseljchak [2.6K]

Answer:

a) The student's overall average for the class is 87.97.

b) He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

Step-by-step explanation:

Weighed average:

To solve this question, we find the student's weighed average, multiplying each of his grade by his weights.

Grades and weights:

Scored 82.5 on the midterm, worth 30%.

Scored 88.6 on the final exam, worth 30%.

Scored 91.6 on the homework, worth 40%.

a. On a 100-point scale, what is the student's overall average for the class?

Multiplying each grade by it's weight:

$A = 82.5*0.3 + 88.6*0.3 + 91.6*0.4 = 87.97$

The student's overall average for the class is 87.97.

b. The student was hoping to get an A in the class, which requires an overall score of 93.5 or higher. Could he have scored high enough on the final exam to get an A in the class?

Score of x on the final class, and verify that the average could be 93.5 or higher. So

$A = 82.5*0.3 + 88.6*0.3 + 0.4x$

$A \geq 93.5$

$82.5*0.3 + 88.6*0.3 + 0.4x \geq 93.5$

$0.4x \geq 93.5 - (82.5*0.3 + 88.6*0.3)$

$x \geq \frac{93.5 - (82.5*0.3 + 88.6*0.3)}{0.4}$

$x \geq 105.425$

He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

3 0

3 years ago