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nadezda [96]
3 years ago
11

After reading The Lord of the Rings, Francesca signs up for archery lessons. At her first lesson, she sets up her target 5 feet

away from her. After lots of practice, she now sets up her target 15 yards away. How many times farther away does Francesca set up her target now?
Mathematics
2 answers:
N76 [4]3 years ago
6 0

Answer:

3 times

Step-by-step explanation:

5x=15

Divide both sides by 5

x=3

Hope this helps

bagirrra123 [75]3 years ago
5 0

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If m 2 n, which inequalities must be true? Check all that apply.
anzhelika [568]

Answer:

(a)\ m+ 2.1 > n + 2.1

(b).\ m - (-4) > n - (-4)

(c)\ 9 +m> 6 + n

Step-by-step explanation:

Given

m > n

Required

Select true inequalities

(a)\ m+ 2.1 > n + 2.1

Subtract 2.1 from both sides

m > n

This is true

(b).\ m - (-4) > n - (-4)

Open brackets

m + 4 > n + 4

Subtract 4 from both sides

m > n

(c)\ 9 +m> 6 + n

m> -9+6 + n

m> n-3

This is also true

8 0
2 years ago
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Find the value of the expression 3m2 + 2p2 − 15 when m = 3 and p = 10.
photoshop1234 [79]
The answer would be 212 :)
6 0
3 years ago
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What’s this answer YALL IM STRUGGLING WITH MATH !!
saul85 [17]

Area: 4900

Perimeter: 280

5 0
2 years ago
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A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
On a number line what are the missing values between 5.1 and 5.2
daser333 [38]

Answer:

Anything from 5.11 to 5.19 can be the missing values.

4 0
3 years ago
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