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USPshnik [31]
3 years ago
8

A car drove at a rate of 32 miles every minute. If the speed per minute remains the same, which method could be used to determin

e the number of miles driven in 25 minutes? *
Mathematics
1 answer:
Radda [10]3 years ago
5 0

Step-by-step explanation:

if the car speeds at a constant rate of 32mi/m

the number of miles travelled in the next 25 min

= 32 mi/m ×25m

800 miles in the next 25 min

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4x + 9 + = 24 matematicas
Harlamova29_29 [7]

Answer:

3.75

Step-by-step explanation:

4x+9=24

4x=24-9

4x=15

x=15/4

x=3.75

7 0
3 years ago
F (x) = (x + 5)º(x - 9)(x + 1)<br> 3
JulijaS [17]

Answer:

3x^3 - 11x^2 + 93x - 105

Step-by-step explanation:

(x+5) (x-9) (x+1) (3) FOIL (First, Outside, Inside, Last)...

x^2 - 9x + 5x - 35 (3x+3) Multiply

3x^3 + 3x^2 - 27x^2 - 27x + 15x^2 + 15x - 105x - 105 Combine Like Terms...

3x^3 - 11x^2 + 93x - 105

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2 years ago
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Anna11 [10]
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7 0
3 years ago
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the outdoor temperaturedeclines 3 degrees each hour for 5 hours. What is the change in temperature at the end of those 5 hours?
hodyreva [135]
15 degrees will be declined in the 5 hours.
3 0
3 years ago
What is 125^2/3 in simplest form? and What is \sqrt[5]({-245} ) ^{5} in simplest form?
Natasha_Volkova [10]
{ 125 }^{ \frac { 2 }{ 3 }  }\\ \\ ={ \left( { 125 }^{ \frac { 1 }{ 3 }  } \right)  }^{ 2 }\\ \\ ={ \left( \sqrt [ 3 ]{ 125 }  \right)  }^{ 2 }\\ \\ ={ 5 }^{ 2 }\\ \\ =25

This is because:

{ a }^{ \frac { m }{ n }  }\\ \\ =\sqrt [ n ]{ { a }^{ m } }

Remember that:

5 x 5 x 5 = 125
5 0
3 years ago
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