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Tems11 [23]
3 years ago
10

Answer number 2 for me plz and thank you

Mathematics
2 answers:
Lostsunrise [7]3 years ago
5 0
In the simplest terms it should be 2:3 (2 boys to 3 girls) But it looks like there should be more to this question
anyanavicka [17]3 years ago
3 0
The answer to the question is 2:3
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Would you rather have a kilogram of quarters or a kilogram of dimes? Why?
True [87]

Answer:kilogram of quarters

Step-by-step explanation:

because quarters equal 25 cents each and it’s a kilogram

8 0
3 years ago
What is 5(6\36+12-3)?<br> (No answer choice)
Ierofanga [76]
The first thing you would do is simplify the inside of the parenthesis to 55/6 using PEMDAS. Next all you do is multiply that by 5 to get 275/6 or 45.833 (repeating) in decimal form.
6 0
4 years ago
How do you do this math? Pls explain your work!
tankabanditka [31]

Answer:

y=14

Step-by-step explanation:

8-4/3-1= 2

so our m=2

now plug it in

4 = 2(1)+b

4 = 2+b

2=b

so it will be

y= 2x+2

y=2(6)+2

y=14

8 0
4 years ago
If a polynomial has four terms, 3x3 5x 6x2 10, which factoring method can be considered? perfect-square trinomial difference of
Tems11 [23]

The factoring method which can be considered for such a cubic tetranomial expression is; factor by grouping sum of cubes.

<h3>What factoring method can be considered for the polynomial?</h3>

It follows from the task content that the order of the Polynomial is 3 and the polynomial is a tetranomial as it contains 4 terms.

On this note, since 3x³ is not a perfect cube, it follows that the best factorisation method for such a polynomial is; factor by grouping sum of cubes.

Read more on factorisation;

brainly.com/question/25829061

#SPJ4

8 0
2 years ago
Solve each problem and show the work for each one.
Cerrena [4.2K]

Answer:

Solve by factoring.

1. 2x^2+9x+26=-4x+5

2x²+9x+4x+26-5=0

2x²+13x+21=0

doing middle term factorization

2x²+7x+6x+21=0

x(2x+7)+3(2x+7)=0

<u>(</u><u>2</u><u>x</u><u>+</u><u>7</u><u>)</u><u>(</u><u>x</u><u>+</u><u>3</u><u>)</u><u>=</u><u>0</u>

<u>either</u>

<u>x</u><u>=</u><u>-</u><u>7</u><u>/</u><u>2</u>

<u>or</u>

<u>x</u><u>=</u><u>-</u><u>3</u><u>.</u>

2.

3x^2-6x-4=0

comparing above equation with ax²+bx+c=0

we get

a=3

b=-6

c=-4

By using quadratic equation

x=\frac{ - b±\sqrt{ {b}^{2} - 4ac } }{2a}

Substituting value

x=\frac{ 6±\sqrt{ {-6}^{2} - 4*3*-4 }}{2*-4}

x=\frac{ 6±\sqrt{ {84}}}{-8}

x=\frac{ 6±2\sqrt{ {21}}}{-8}

-8x=6±2√21

taking positive

-8x=6+2√21

x=\frac{6+2√21}{-8}

x=-\frac{3+√21}{4}

taking negative

-8x=6-2√21

x=\frac{6-2√21}{-8}

x=-\frac{3-√21}{4}

8 0
3 years ago
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