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lara31 [8.8K]
3 years ago
13

This is confusing (2x+y)^2−(x−2y)^2

Mathematics
2 answers:
belka [17]3 years ago
8 0

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em><em>⤴</em>

Iteru [2.4K]3 years ago
5 0

Answer:

{(2x + y)}^{2}  -  {(x - 2y)}^{2}

<  {(x + y)}^{2}  =  {x}^{2}  + 2xy +  {y}^{2}  >

<  {(x - y)}^{2}  =  {x}^{2}  - 2xy +  {y}^{2}  >

{(2x)}^{2}  + 2(2x)(y) +  {(y)}^{2}  -  {(x)}^{2}  - 2(x)(2y) +  {(2y)}^{2}

{4x}^{2}  + 4xy +  {y}^{2}  -  {x}^{2}  - 4xy +  {4y}^{2}

{4x}^{2}   -  {x}^{2}  +  {4y}^{2}  +  {y}^{2}

= {3x}^{2}  +  {5y}^{2}

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