I need help please help me asap!

One of the roots of the equation 5x2−36x+t=0 is five times as big as the other root. Find the value of t.

Bas_tet [7]

Answer:

t = 36

Step-by-step explanation:

If one of the roots is "a", the equation can be factored as ...

(5x -a)(x -a) = 0

5x^2 -6ax +a^2 = 0

Comparing terms to the given equation, we see that ...

-6ax = -36x

a = 6 . . . . . . . . divide by -6

Then ...

a^2 = t

36 = t . . . . . . . substitute 6 for a

_____

The roots are 6 and 6/5.

4 0

3 years ago

Slope Of (5,-5) and (-1,-5)

Alex777 [14]

$\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{-5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-5}-\stackrel{y1}{(-5)}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{5}}}\implies \cfrac{-5+5}{-6}\implies \cfrac{0}{-6}\implies 0$

4 0

3 years ago

A pack of 100 wolves on a remote island are suffering from a new disease. Let W(t) be the number of sick wolves at time t. Suppo

Olin [163]

Answer:

$b)\,\frac{dW}{dt}=kt\sqrt{W}, \,W(0)=10$

Step-by-step explanation:

Initial number of sick wolves = W(0) = 10

At time t, no. of sick wolves = W(t)

Given that disease is spreading at a rate proportional to the product of the time elapsed and the square root of the number of sick wolves:

$\frac{dW}{dt}=kt\sqrt{W}$

Mathematical model of above case is:

$\frac{dW}{dt}=kt\sqrt{W}, \,W(0)=10$

5 0

3 years ago

Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (x,y) be the unkno

gizmo_the_mogwai [7]

Answer:

The other endpoint of the segment is $(-18,-7)$ .

Step-by-step explanation:

The midpoint of the points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the following formula:

$(x_m,y_m)=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )$

where $(x_m,y_m)$ = coordinates of the midpoint.

We know that the midpoint is (-15, 2) and an endpoint is (-12, 11). Substituting the information we have gives:

$(-15,2)=(\frac{x_1-12}{2}, \frac{y_1+11}{2} )$

To find $x_1$ we need to solve this equation:

$-15=\frac{x_1-12}{2} \\\\\frac{x_1-12}{2}=-15\\\\\frac{2\left(x_1-12\right)}{2}=2\left(-15\right)\\\\x_1-12=-30\\\\x_1-12+12=-30+12\\\\x_1=-18$

and to find $y_1$ we need to solve this equation:

$2= \frac{y_1+11}{2} \\\\\frac{y_1+11}{2}=2\\\\\frac{2\left(y_1+11\right)}{2}=2\cdot \:2\\\\y_1+11=4\\\\y_1=-7$

The other endpoint of the segment is $(x_1,y_1)=(-18,-7)$ .

5 0

3 years ago

How do i find the vertical asymptote?

levacccp [35]

Answer:

find the value of x that makes the denominator zero: x = 7

Step-by-step explanation:

A vertical asymptote shows up where the denominator is zero. As the denominator gets closer to zero, the function value gets larger without bound (unless there is a numerator factor that cancels the one in the denominator).

To find the value of x at the vertical asymptote, solve the equation ...

denominator = 0

x - 7 = 0

x = 7 . . . . . . . add 7 to both sides

7 0

3 years ago