-17 17
----- -(-17) ----
8 ---- -8
8
First we write equation that consist coordinates of center and radius. That formula goes like this:
(x-x1)^2 + (y-y1)^2 = r^2
x and y are coordinates on any point on circle
x1 and y1 are coordinates of center of circle.
r is radius of that circle. now we need to express our values for center and radius andf square binoms and see what matches in our options.
(x-3)^2 + (y-8)^2 = 5^2
x^2 + y^2 -6x -16y +48 = 0
The answer is first option.
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Answer:
1). x = 10 m
2). x = 15 cm
3). x = 5 yd
4). AB = 10 units
Step-by-step explanation:
1). By Pythagoras theorem in the given triangle,
a² + b² = c²
Where 'c' = Hypotenuse
a and b = Legs of the right triangle
By substituting measures of the sides in the formula,
x² = 8² + 6²
x = 
x = 10 m
2). By using Pythagoras theorem in this triangle,
x² = 9² + (12)²
x² = 81 + 144
x = 
x = 15 cm
3). By Pythagoras theorem,
(13)² = x² + (12)²
169 = x² + 144
169 - 144 = x²
25 = x²
x = 5 yd
4). If BD is a perpendicular bisector of AC,
AD = CD = 6 cm
By Pythagoras theorem in ΔABD,
AB² = BD² + AD²
AB² = 8² + 6²
AB = 
AB = 10 units
Answer:
- 880 lbs of all-beef hot dogs
- 2000 lbs of regular hot dogs
- maximum profit is $3320
Step-by-step explanation:
We can let x and y represent the number of pounds of all-beef and regular hot dogs produced, respectively. Then the problem constraints are ...
- .75x + 0.18y ≤ 1020 . . . . . . limit on beef supply
- .30y ≤ 600 . . . . . . . . . . . . . limit on pork supply
- .2x + .2y ≥ 500 . . . . . . . . . . limit on spice supply
And the objective is to maximize
p = 1.50x + 1.00y
The graph shows the constraints, and that the profit is maximized at the point (x, y) = (880, 2000).
2000 pounds of regular and 880 pounds of all-beef hot dogs should be produced. The associated maximum profit is $3320.