In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.

For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).

So, we need to multiply (x-7) and (x-4) by foil method.

We get

(x-7)(x-4) = x*x + x* -4 -7*x -7*-4

x^2 -4x -7x +28.

Combining like terms, we get

-4x-7x = -11x

x^2 -4x -7x +28 = x^2 -11x +28.

Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.

We get

1(x^2 -11x +28) = x^2 -11x +28.

Therefore, the required quadratic function in standard form is x^2 -11x +28.

6 0

3 years ago

Find the value of x. A. x= 1 B. x=5 C. x=19 D. x=37

Strike441 [17]

Triangle WYZ and triangle TWY are congruent, therefore WZ = TW
WZ = TW
3x - 5 = 2x
3x - 2x = 5
x = 5

The value of x is 5

6 0

3 years ago

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