Answer:
- Q3. 12 units
- Q4. 6.33 units
- Q5. 66.19°
Step-by-step explanation:
Q3
DE and DF are legs and EF is hypotenuse
- DE = √EF² - DF²
- DE = √13² - 5² = √169 - 25 = √ 144 = 12
- DE = 12 units
Q4
PR is opposite side of angle Q and RQ is adjacent side
- tan 54 = PR/RQ
- tan 54 = PR / 4.6
- PR = 4.6tan 54
- PR = 6.33 units
Q5
As previous question, using tan as BC is opposite and AC is adjacent leg of angle A
- tan A = 6.8/3
- tan A = 2.266
- A = arctan (2.266)
- A = 66.19°
Answer:
The explicit formula is Tn = 18[(2/3)^(n-1)]
Where n is the term we are looking for
Step-by-step explanation:
Here, we want to get an explicit formula to model the equation
Now, F(2) = 2/3 * f1 = 2/3 * 18 = 12
F(3) = 2/3 * f(2) = 2/3 * 12 = 8
F(4) = 2/3 * F(3) = 2/3 * 8 = 16/3
F(5) = 2/3 * 16/3 = 32/9
Thus, seeing how the equations are progressing, we can definitely see a pattern.
That is Tn = (2/3)^(n-1)(18)
Y=2x^3 is nonlinear, since it's a cube equation. y=x+5 is linear, because it's a line with y intercept (0,-5) and slope 1. y=\sqrt(x-5) is nonlinear, because it's a quadratic equation when reversing x and y. 5x+5y=25 is equal to x+y=5 ot y=-x+5, which is also linear. y=x^2/2 is a quadratic equation, so it's nonlinear.
Answer: 4 terms
Step-by-step explanation:
-4a , 8c, -4b, and 3
Hello,
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Thanks for the incorrect formula!
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I have tested (fog)(x) ,(f*g)(x) and finally (f+g)(x)
f(x)=6x++++++++++++++++++++++++3
g(x)=x-7
(f+g)(x)=6x+3+x-7=7x-4
(f+g)(3)=7*3-4=17
Answer B
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