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-BARSIC- [3]
3 years ago
9

Find the midpoint of the line segment with the given endpoints. (14, -6), (13, 14)​

Mathematics
2 answers:
Cloud [144]3 years ago
3 0

Answer:

Step-by-step explanation:

23

Flura [38]3 years ago
3 0

Answer:

(\frac{27}{2}, 4 )

Step-by-step explanation:

Use the midpoint formula

midpoint = [\frac{1}{2}(x₁ + x₂), \frac{1}{2}(y₁ + y₂ ) ]

with (x₁, y₁ ) = (14, - 6) and (x₂, y₂ ) = (13, 14), hence

[\frac{1}{2}(14 + 13), \frac{1}{2}(- 6 + 14) ]

= (\frac{27}{2}, 4)

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\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta

\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0

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If you use those identities, for \alpha=x,\ \beta=\dfrac{\pi}{2}, you get:

\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x

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\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x
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Answer:

<h3>495 different ways</h3>

Step-by-step explanation:

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