Answer:
320 in.²
Step-by-step explanation:
Let's think of the shape as a normal rectangle with a height of 16 inches. Now all we need is the length. If you look at the right corner, it looks like a piece has been cut out. Since that piece has the same length and height of 8 inches, it is a square. This tells us the missing length of the entire length of the rectangle. Now the length of the rectangle is 16 inches + 8 inches, which is 24 inches.
The total area of the rectangle is 16 × 24, which is 384.
Then from the total area, we just need to subtract the area of the cut-out part. The area of the cut-out square is 8 × 8, which is 64.
384 - 64 = 320
The total surface area of the following complex shape is 320 in.²
Y = 12x where x is the # of students and y is the # of adults
Or for every 12 students there's 1 adult
(3x + 4)³ = 2197
Taking the cube root in this case is easier, although we can do it the extended way which is complicated.
![\sqrt[3]{(3x+4)^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%283x%2B4%29%5E3%7D%20)
=
![\sqrt[3]{2197}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2197%7D%20)
3x + 4 = 13
Now solve normally.
subtract 4
3x + 4 = 13
-4 -4
3x = 9
Divide by 3 to isolate 3
3 and 3 cancels out
x = 3
Answer:
D. 62˚
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let X be number of woodland bicyles and Y grande expedition
Our objective is to maximize profit
Z = 250x+350Y
Constraints are: 2x+3y<450 and
x+y<375
(given)
Solution gives negative y. Hence intersecting point is not within constraint.
So choices satisfying the constraints would be min of 225, 375 for x and min of 150,375 for x
i.e x=225 and y =150
To maximize revenue 225 Woodland and 150 Grande to be produced
