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pshichka [43]
3 years ago
12

What is the value of x?45°(2x - 5)°​

Mathematics
2 answers:
vichka [17]3 years ago
7 0

Answer:

50

Step-by-step explanation:

2x25=50-5=45

zepelin [54]3 years ago
6 0

Answer:

70

Step-by-step explanation:

edgenuity 20200000000000000000000000000000000

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Which equation can be solved using the expression StartFraction negative 3 plus-or-minus StartRoot (3) squared + 4 (10) (2) EndR
katen-ka-za [31]

Answer: B.  2 = 3x + 10x2

Step-by-step explanation:

This is the concept of quadratic equations; We required to find the type of equation that can be solved using the model that has been used to solve the equation such that the answer is:

[-3+-sqrt(3^2+4(10)(2))]/(2(10))

The formual that was applied here was a quadratic formula given by:

x=[-b+\-sqrt(b^2-4ac)]/2a

whereby from the our substituted values above,

a=10,b=3 and c=-2

such that the quadratic equation will be:

10x^2+3x-2 

3 0
3 years ago
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The half life of a radioactive kind of cadmium is 14 years. How much will be left after 28 years, if you start with 72 grams of
nlexa [21]

Answer:

18 grams

Step-by-step explanation:

8 0
3 years ago
Andrew has a four-year college loan for $20,000. The lender charges a simple interest rate of 5 percent. How much interest will
Olegator [25]

Given that loan amount P=20000

Interest rate r=5% = 0.05

Time of loan t=4 years

Now to find the interest amount we just plug those values into formula

simple interest = P × r × t

simple interest = 20000* 0.05* 4

simple interest = 1000 * 4

simple interest = 4000

Hence final answer is choice b. $4000.

7 0
3 years ago
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Find the HCF and LCM of: x^3+27,2x^3-6x^2+18x,x^2-3x+9​
r-ruslan [8.4K]

Answer:

hcf:3x^3-6x^2+y^2-3x+54

lcm:2(x+3)(x^2-3x+9)(x^3-3x^2+9)(y^2-3x+9)

7 0
2 years ago
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notsponge [240]
Use the Pythagorean theorem, tan is y/x so y = -3 and x= -2. Because cos is negative and R is always positive. You need to find R- which is the hypotenuse;
3^2 + 2^2 = r^2
9 + 4 = r^2
13 = r^2
√13 = r.

So you already have tan<span>θ, 
cot</span><span>θ= 2/3

sin</span>θ= -3/√13 BUT
you have to rationalize, so you get -3 √13/ 13

cscθ= √13/ -3

cosθ= -2/ √13 BUT
you have to rationalize, so you get -2√13/ 13

secθ= √13/ -2
4 0
3 years ago
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