Answer:
Step-by-step explanation:
we know that
The surface area of a rectangular prism is equal to the area of its six rectangular faces
using the net
The surface area is equal to
![SA=2[(16)(6)]+2[(16)(8)]+2[(8)(6)]](https://tex.z-dn.net/?f=SA%3D2%5B%2816%29%286%29%5D%2B2%5B%2816%29%288%29%5D%2B2%5B%288%29%286%29%5D)
1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
multiply 300 by 7 and then you should be able to finish the equation
The sunflower is 2.387 meters tall.
The question is asking: which rounding will result in the greatest value?
To see, we need to round 2.387 to meter, tenth meter, and hundredth meter.
Meter - 2 meters
Tenth meter - 2.4 meters
Hundredth meter - 2.39 meters
As you see, rounding to the tenth meter gives the greatest value of 2.4. Therefore, Bahir should use a decimal rounded to the tenth meter.
Answer:
1/0.4=10/4=5/2...............
