Answer:
db / dt = kb
this becomes b(t) = Ce^(kt)
C = 100, the initial population
P(1) = 420 = 100 e^(1k)
4.2 = e^k
ln 4.2 = k
a) thus, b(t) = 100 e^(t ln 4.2)
b) b(3) = 100 e^(3 ln 4.2)
c) growth constant will still be ln 4.2 (constant percentage of populatioin)
d) 10000 = 100 e^(t ln 4.2)
100 = e^(t ln 4.2)
ln 100 = t ln 4.2
t = ln 100 / ln 4.2
Step-by-step explanation:
Answer:
None of the answer options are correct.
Step-by-step explanation:
A confidence interval of the mean is a range within is expected to find the population mean, with a certain degree of confidence.
In this case, the population mean is the average price for a lunch for a n=25 sample.
The interpretation of a 95% confidence interval of (14.43,17.57) should be that there is a 95% of confidence that the population mean (average price for a lunch out of a sample of 25 lunches) is within this interval.
24 is the answer to your question
