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saw5 [17]
3 years ago
15

Write an equation to solve each problem and then solve it. The sum of three consecutive integers is 54. Find the integers. if th

e smallest integer is x, what will the equation be?
Mathematics
1 answer:
likoan [24]3 years ago
7 0

Answer:

It is 17,18 and 19

Step-by-step explanation:

Consecutive numbers are

x, x+1, x+2

x+x+1+x+2=54

3x+3=54

-3       -3

3x=51

x=17

17

17+1=18

17+2=19

17, 18 and 19

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Answer:

w=A/l

Step-by-step explanation:

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3 years ago
Pedro, Alex, and Jaime are having a three-point contest. Each boy takes six turns and records the number of three-pointers he sh
bazaltina [42]
First, reorder the numbers for each person. 
The median is basically the middle number. If there are 2 middle numbers, then take the average of the two of them. 

Pedro: 4, 5, 6, 7, 8, 9    
The 2 middle numbers are 6 and 7. The average of 6 and 7 is 6.5 .
Median = 6.5

Alex: 3, 5, 5, 5, 9, 9
The 2 middle numbers are 5 and 5; so basically, the average is 5.
Median = 5

Jaime: 3, 4, 6, 8, 8, 9
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So the answer should be Jaime. 
7 0
3 years ago
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How do you slove 2/3 (9x -6) = 14
Ivanshal [37]

Answer:

x=3

Step-by-step explanation:

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2

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(

2

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6x+−4=14

6x−4=14

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5 0
3 years ago
Given a function <img src="https://tex.z-dn.net/?f=f%28x%29%3D3x%5E4-5x%5E2%2B2x-3" id="TexFormula1" title="f(x)=3x^4-5x^2+2x-3"
Levart [38]

Answer:

\huge\boxed{f(-1) = -7}

Step-by-step explanation:

In order to solve for this function, we need to substitute in our value of x inside to find f(x). Since we are trying to evalue f(-1), we will substitute -1 in as x to our equation.

f(-1) = 3(-1)^4 - 5(-1)^2 + 2(-1) - 3

Now we can solve for the function by multiplying/subtracting/adding our known values.

Starting with the first term to the last term:

  • 3(-1)^4 = 3

<u><em>WAIT</em></u><em>!</em><em> How is this possible? </em>-1^4 = -1 (according to my calculator), and 3 \cdot -1 = -3, not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use -2^2 as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

- Brackets

- Exponents

- Multiplication/Division

- Addition/Subtraction

Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than  being <em>"-2 squared"</em> - it's <em>"the negative of of 2 squared."</em>

Tying this back into our problem, the squared method would only be true if it looks like -1^4. However, since we're substituting in -1, it looks like (-1)^4, so the expression reads out as "<u><em>-1 to the fourth.</em></u>"

MULTIPLYING -1 by itself 4 times results in -1\cdot-1\cdot-1\cdot-1=1.

Applying this logic to our original term, 3(-1)^4:

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Therefore, our first term is 3.

Let's move on to our second and third terms.

Second term: -5x^2

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Applying the same logic from our first term:

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Third term: 2x

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-3 is just -3, no influence of x.

Combining our terms, we have 3-5-2-3.

This comes out to be -7, hence, the value of f(-1) for our function f(x)=3x^4-5x^2+2x-3 is <u>-7</u>.

Hope this helped!

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c

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