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Trava [24]
3 years ago
5

What is the largest 5-digit number that is a multiple of both 4 and 9?

Mathematics
1 answer:
ki77a [65]3 years ago
7 0

Answer:

Step-by-step explanation:

The last two digits have to be divisible by 4

The entire number's digits have to add to a multiple of 9. So I will start with 99964

64 does not add up to a multiple of 9. so that's not the answer. 64 is divisible by 4 but not 9

Move on 99968 which has the same problem.

99972 works!!!!

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The given equality hold true when x = 2.

Put x = 2 in inequality.

2(2) + 3 = 4+3 = 7 = R.H.S.

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Hence for x = 2, 4 and 6, the above inequality holds true.

Hope this helps!
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The area of a rectangle is represented by the expression 6x³y5. Which of the following could be the
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The length and width of the rectangle are: 2x^2y^2 , 3xy^3

<h3>What is the area of the rectangle?</h3>

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

The area of a rectangle is represented by the expression 6x^3y^5.

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So, the length and width of the rectangle are: 2x^2y^2 , 3xy^3

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7 0
2 years ago
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Vikentia [17]
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5 0
3 years ago
The stem-and-leaf plot shows the ages of people at a family reunion.
klio [65]

Answer:

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2) It is 4 because there is one person over 65. In the second row we ignore the 7 and there are 3 people in the 7 row.

5 0
2 years ago
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