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Semmy [17]
3 years ago
9

What is a demand schedule? A. a chart that shows the demand for a type of product at various prices B. a graph that shows the de

mand for a product at a single price point C. a chart that shows the demand for a product at various prices
Mathematics
2 answers:
RUDIKE [14]3 years ago
7 0

Answer:

The answer to this question is c

Step-by-step explanation:

timama [110]3 years ago
4 0
C is the answer the answer to this question is c
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si lan varlgo 2x4x4x2.5

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la nidra si margo

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Write a real world problem that can be represented by the expression 5x + 10
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The initial fee for a gym membership is $10 and for each month of the membership it costs $5. Jem has been going to the gym for 8 months, what is the total cost?
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Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams
hram777 [196]

Answer:

X(16)=25.71grams

Step-by-step explanation:

let X(t) denote grams of C formed in  t mins.

For X grams of C we have:

\frac{2}{3}Xg of A and \frac{1}{3}Xg of B

Amounts of A,B remaining at any given time is expressed as:

40-\frac{2}{3}Xg of A and  50-\frac{1}{3}Xg  of B

Rate at which C is formed satisfies:

\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt  \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}

Apply the initial condition,X(0)=0 ,to the expression above

0=90-\frac{1}{c} \ \ ->c=\frac{1}{90}\\\therefore\\X(t)=90-\frac{1}{kt+\frac{1}{90}} \ \ ->X(t)=90-\frac{90}{90kt+c}

Now at X(8)=15:

15=90-\frac{90}{90\times 8k+1}  \ ->75=\frac{90}{720k+1}\\k=0.0002778

Substitute  in X(t) to get

X(t)=90-\frac{90}{0.0002778t\times 90+1}\\X(t)=90-\frac{90}{0.25t+1}\\But \ t=16\\\therefore X(t)=90-\frac{90}{0.025\times16+1}\\X(t)=25.71

5 0
2 years ago
Please help with this thank you
RUDIKE [14]

1/4 is 25 percent so it is still 40.00

6 0
2 years ago
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