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3 years ago

Round each number to three significant figures.a. 3.14159 b. 6.12356c. 4.56787

Mathematics

1 answer:

Karolina [17]3 years ago

4 0

Answer:

The round off values are- 3.14, 6.12, and 4.57 respectively.

Step-by-step explanation:

The given value to which we have to round off is a. 3.14159 b. 6.12356 c. 4.56787

In order to round off the number we must keep in mind that there should be three digits in total and we will increase the value by one if the right-hand side value is more than 5.

Thus round off figure of 3.14159 is 3.14.

The round off figure of 6.12356 is 6.12.

The round off figure of 4.56787 is 4.57.

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if a knockout tennis competition starts with 64 players how many runs will it take to reach the grand final show your steps usin

snow_tiger [21]

Answer:

5 runs

Step-by-step explanation:

Initial number is 64 players

<u>Number of players reduce twice every run and will be equal to 2 to reach the grand final</u>

64*(1/2)^x = 2
(1/2)^x = 1/32
2^-x = 2^-5
-x = -5
x = 5

Number of runs is 5

64 > 32 > 16 > 8 > 4 > 2

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3 years ago

What is 10 times as much as 24.735?

Otrada [13]

Answer: 247.35

Step-by-step explanation:

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2 years ago

Would it be B? Let me know

IgorC [24]

Answer:

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Step-by-step explanation:

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2 years ago

If the diameter of a cylinder is 18 inches, the radius of the cylinder is 9 inches.

Afina-wow [57]

Answer:

True

Step-by-step explanation:

A cylinder has two circles as its bases, and the diameter formula is:

2r = d

So if you plug in:

2r = 18

--- ---

2 2

r = 9

So it will be true.

Hope this helped.

7 0

3 years ago

A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl

Andrew [12]

Answer: $\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$ or $\dfrac{228}{91885}$ .

Step-by-step explanation:

Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.

The total number of cards in a deck 52

Number of faces cards in a deck = 12

Number of cards not face cards = 40

The total number of combinations of drawing 9 cards out of 52 cards = $^{52}C_9$

Now , the combination of 9 cards such that exactly 6 of them are face cards = $^{12}C_{6}\times^{40}C_3$

Now , the probability that the hand contains exactly 6 face cards will be :-

$\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$

$=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}$

Hence, the probability that the hand contains exactly 6 face cards. is $\dfrac{228}{91885}$ .

6 0

3 years ago