The expression (n+3) represents the measure of an exterior angle of a regular octadecagonal.
Because the polynomial has degree 2, we can assume that there are 2 solutions (roots), whether real or imaginary.
You can subtract 60 in order to put this in standard form
48x^2+44x-60 = 0
From there, just put a,b, and c into the quadratic formula and you're good to solve for your answers.
(-b+-sqrt(b^2-4ac))/2a
(-44+-sqrt(44^2-4(48)(-60)))/2(48)
Then solve.
There is probably a better way, but this should give you the two roots/solutions.
Answer:
15$
Step-by-step explanation:
15$
Answer:
8
Step-by-step explanation:
Length = 2x-4
Width = x+1
Let x=3 and find the length and width
Length = 2*3-4 = 6-4 =2
Width = x+1= 3+1 =4
The area is given by
A = l*w = 2*4 = 8
Answer:
24
Step-by-step explanation:
Just subtract the first quartile form the third quartile.
third quartile - first quartile
32 - 8 = 24 IQR
FIRST quartile: 8
SECOND quartile: 20
THIRD quartile: 32
So the IQR is 24
Hope this helps :)
