Answer:
Q8) True
Q9) First ionization energy
Q10) Metal oxides
Explanation:
A common property of group one elements (alkali metals) is their combination with water to form basic solutions. E.g 2K(s)+2H2O(l)→2KOH(aq)+H2(g).
The distance of the outermost electron in the atom from the nucleus is inversely related to the first ionization energy. As the distance between the outermost electron and the nucleus in group 17 elements gets larger, the corresponding first ionization energies of elements in the group gets smaller.
Group 1 elements can combine with oxygen to give metal oxides. E.g 4K + O2 --> 2 K2O
It absorbed 41,600 joules.
Explanation:
If the sample of sucrose burnt in the calorimeter releases 41600Joules of heat, then the water in the calorimeter will absorb 41600J.
The heat lost by burning the sucrose in the calorimeter is also the heat gained by the water therein.
A calorimeter is a device by prevents heat loss to the environment in any form.
It is specially designed to minimize heat loss by conduction, convection radiation.
Therefore, since no heat is lost, the heat released by burning the sucrose is used in heating the water there.
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We have to get the amount of nitrogen to be consumed to get 0.75 moles of ammonia.
The amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is: 10.5 grams.
Ammonia (NH₃) can be prepared from nitrogen (N₂) as per following balanced chemical reaction-
N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)
According to the above reaction, to prepare 2 moles of ammonia, one mole of nitrogen is required. Hence, to prepare 0.75 moles of ammonia, 
moles = 0.375 moles of nitrogen is required.
Molar mass of nitrogen is 28 grams, i.e, mass of one mole of nitrogen is 28 grams, so mass of 0.375 moles of nitrogen is 0.375 X 28 grams=10.5 grams of nitrogen.
Therefore, the amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is 10.5 grams.
Answer:
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