Finding the image need help !

a certin shade of green paint is made from 5 parts yellow mixed with three parts blue. if 2 cans of yellow are used, how many ca

andrew-mc [135]

__Brainliest if helped!

5 Parts Yellow with 3 Parts blue
5Yellow with 3 Blue
1Yellow would be with 3/5 Blue
Hence ,
2 Yellow = (3/5)*2 Blue =6/5 Cans of blue or 1.2Cans of blue.

4 0

3 years ago

The length of side X is 36.25 cm to the nearest hundredth of a centimeter what is the length of y

goldenfox [79]

Answer:

<h3>The length of y is 62.82 cm.</h3>

Step-by-step explanation:

We are given a right triangle with an angle 30°.

Opposite side of angle 30° is x and adjacent side is y.

Also, given length of side x=36.25 cm.

In order to find the value of y, we need to apply tangent trigonometrical ratio.

We know,

$tan \theta =\frac{Opposite \ Side}{Adjacent \ Side}$

Therefore,

$tan \theta =\frac{x}{y}$

Plugging values of $\theta =30^o$ and x=36.25, we get

$tan 30^o=\frac{36.25}{y}$

Plugging value of $tan 30^o=0.577$ in above equation, we get

$0.577=\frac{36.25}{y}$

On multiplying both sides by y, we get

$0.577\times y=\frac{36.25}{y}\times y$

0.577y=36.25

Dividing both sides by 0.577, we get

$\frac{0.577y}{0.577} =\frac{36.25}{0.577}$

y=62.82

<h3>Therefore, the length of y is 62.82 cm.</h3>

3 0

3 years ago

The area of a parallelogram is 125 square inches and the height of the parallelogram is 10 inches. What is the lenght of the bas

kipiarov [429]

Answer:

12.5 inches is the correct answer.

Step-by-step explanation:

I can bet you with brainliest post if it is correct mark me brainliest and wrong then spam me(;

6 0

3 years ago

A restaurant offered cooking classes on 20 of the 30 day in November.

Stells [14]

The percentage is 66.6%.

3 0

3 years ago

Read 2 more answers

Drag the expressions into the boxes to correctly complete the table.

lora16 [44]

Answer:

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form $ax^n$ .

Here:

$n$ = non-negative integer

$a$ = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

$x^4+\frac{5}{x^3}-\sqrt{x}+8$

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains $\sqrt{x}$ , so it is not a polynomial.

Also it contains the term $\frac{5}{x^3}$ which can be written as $5x^{-3}$ , meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression $x^4+\frac{5}{x^3}-\sqrt{x}+8$ is not a polynomial.

Given the expression

$-x^5+7x-\frac{1}{2}x^2+9$

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

$\left|x\right|^2+4\sqrt{x}-2$

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

$x^3-4x-3$

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

$\frac{4}{x^2-4x+3}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

3 0

3 years ago