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trasher [3.6K]
3 years ago
7

If f(x) = 1 – x2 + x3, then f(-1) =

Mathematics
1 answer:
Monica [59]3 years ago
4 0

Answer:

Step-by-step explanation:

f(-1)= 1 - (-1)^2 + (-1)^3 = 1 - 1 - 1 = 0 - 1 = -1

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A soccer ball is kicked toward the goal. The height of the ball is modeled by the function h(t) = −16t2 + 48t where t equals the
zlopas [31]
1. The function h(t)=-16t^{2}+48t is a parabola of the form ax^{2}+bx. The the formula for the axis of symmetry of a parabola is x= \frac{-b}{2a}. We can infer from our function that a=-16 and b=48, so lets replace those values in our formula:
x= \frac{-b}{2a}
x= \frac{-48}{-2(16)}
x= \frac{-48}{-32}
x= \frac{3}{2}
x=1.5
We can conclude that to the left of the line of symmetry the ball is reaching its maximum height, and to the right of the line of symmetry the ball is falling.

2. Lets check how much time the ball takes to reach its maximum height and return to the ground. To do that we are going to set the height equal to zero:
0=-16t^{2}+48t
-16t(t-3)=0
t=0 or t-3=0
t=0 or t=3
From our previous point we know that the ball reaches its maximum time at t=1.5, which means that <span>it takes 1.5 seconds to reach the maximum height and 1.5 seconds to fall back to the ground.</span>

7 0
3 years ago
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A single 6-sided die is rolled. What is the probability of rolling a number
ruslelena [56]

Answer:

what are your answer choices?

Step-by-step explanation:

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Jamal is 12 years older than twice Stephanie’s age. The sum of their ages is 45. A. If Stephanie’s age is represented by x, writ
amm1812

Answer:

Jamal's age = 2×x+12= 2x+12

sum og ages = 45

2x+12+x= 45

=3x+12=45

=45-12= 3x

= 32=3x

x= 32/3= 10.67

2x+13 =21.34+12= 33.34

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4 0
3 years ago
Divide (13 + 6х2 +11х + 6) by (х + 2)
adoni [48]

Answer:

(13+6x²+11x+6)÷(x+2)

(6x²+11x+19)÷(x+2)

(6x²+11x+19)÷(x+2)

5 0
3 years ago
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0
3 years ago
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