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irinina [24]
4 years ago
12

Solve for y in x+0.25y=1.5

Mathematics
1 answer:
IRISSAK [1]4 years ago
5 0

Answer:

Y=-4x+6

Step-by-step explanation:

Step 1: Add -x to both sides.

X+0.25y+-x=1.5+-x

0.25y=-x+1.5

Step 2: Divide both sides by 0.25.

0.25y/0.25=-x+1.5/0.25

Y=-4x+6

Hope I helped

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Find the equation of the line that passes through the point (6,14) and is parallel to the equation below.
gogolik [260]

Answer:

y = 2x/3 + 10 ; C

Step-by-step explanation:

To write the equation of a straight line, we have the general form as;

y = mx + b

where m is the slope and b is the y intercept

Mathematically from the equation given, the slope value is 2/3

When two lines are parallel to each other , the value of their slopes are the same

What this mean is that the value of the slope of the second line is 2/3

So we have the second line as;

y = 2x/3 + b

To get the value of b, we use the given point where the line passes through

The given point according to the question is the point (6,14)

so using this coordinates, we have

14 = 2/3(6) + b

14 = 4 + b

b = 14-4

b = 10

So the equation of the new line is;

y= 2/3x + 10

3 0
3 years ago
HELP ME please i need to solve this
nata0808 [166]

add 0+1+2+3+4 = 10

divide 10÷5 = 2

add 15+8+3+3+1 = 30

divide 30÷5 = 6

the ratio is 2:6 which simplifies to 1:3 by the means of lates per student. In other words there is one late per 3 students.

5 0
3 years ago
If f(a) = 2a ^ 3 + 3a ^ 2 + 5 , find f(- 2)
UkoKoshka [18]
<h2>Answer: 1</h2>

Step-by-step explanation:

Just plug in -2 anywhere you see an <u>a</u>

f(a)=2a^3+3a^2+5\\f(-2)=2(-2)^3+3(-2)^2+5\\f(-2)=2(-8)+12+5\\f(-2)=-16+12+5\\f(-2)=1

8 0
2 years ago
Read 2 more answers
In each figure below, find m∠1 and m∠2 if a║b. Show your work with statements.
velikii [3]

Answer:

<1=105 and <2=75.

Step-by-step explanation:

<1+<2=180, and 75+<1=180, so 180-75=105=<1. 105+<2=180, so 180-105=75=<2.

7 0
3 years ago
What is the y-intercept of the equation of the line that is perpendicular to the line y = 3/5x + 10 and passes through the point
melisa1 [442]
The slope of the perpendicular line is the negative reciprocal of that of the given line, so is
  -1/(3/5) = -5/3
Then the point-slope equation of the perpendicular line can be written as
  y = (-5/3)(x -15) -5
  y = (-5/3)x +20

The y-intercept of the perpendicular line is y=20.

7 0
3 years ago
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