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Galina-37 [17]
3 years ago
5

Twenty added to the sum of a number and six is twenty-seven

Mathematics
2 answers:
Mila [183]3 years ago
8 0

-- Call the number 'N'.

-- The sum of the number and six is (N + 6).

-- Twenty added to it is    20 + (N + 6)

-- That whole thing is twenty-seven           

                                              <u>20 + (N + 6) = 27</u>

Subtract  20  from each side:          (N + 6) = 7

Subtract  6  from each side:            <em>  N      =  1

</em>
==================================

Check:<em>  </em>

Put your solution into the statement and see if the statement is true.

     "Twenty added to the sum of (1 and six) is twenty-seven."<em>

</em>
That's true.            <em>yay !</em><em>
</em>

Ierofanga [76]3 years ago
5 0
For six is twenty seven will look like this 

6 = 27 

sorry i don't know what twenty added to the sum of a number is...
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Convert the mixed number 4\ \frac{2}{8} as a decimal number.

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Then, knowing that 4.25 acres cost $165,000 , divide this amount by 4.25 acres to find the cost of each acre.

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Read 2 more answers
Find the nature of the root
GREYUIT [131]

Answer:

1) Real and same.

2) Real and distinct

3) Real and distinct

4) Real and distinct

5) Real and distinct

6) Real and distinct

7) Real and distinct

8) Real and distinct

Step-by-step explanation:

If a quadratic equation is in the form of ax² + bx + c = 0, then Discriminant of the equation D = b² - 4ac, which governs the nature of roots the equation has.

If D > 0, then there will be two different real roots.

If D = 0, then two same and real roots.

If D < 0, then two distinct but imaginary roots.

Now, 1) x² + 6x + 9 = 0 has D = 6² - 4 × 9 × 1 = 0. So, there will be two same and real roots.

2) 5x² - x = 4x² + 2

⇒ x² - x - 2 = 0

It has D = (-1)² - 4 × 1 × (-2) = 9. Therefore, the roots will be two distinct and real.

3) \frac{2}{x} + \frac{3}{x} = x - 4

⇒ 5 = x² - 4x

⇒ x² - 4x - 5 = 0.

So, D = (-4)² - 4 × (1) × (- 5) = 36. So, the equation has two real and distinct rools.

4) x(x - 5) = 4(5 - x)

⇒ x² - x - 20 = 0

Hence, D = (-1)² - 4 × 1 × (-20) = 81

So, the roots will be real and distinct.

5) x² + 7x + 1 = 0 has D = 7² - 4 × 1 × 1 = 45

So, the roots will be real and distinct.

6) 2x² + 9x + 3 = 0, has D = 9² - 4 × 2 × 3 = 57.

Hence, the roots will be real and distinct.

7) 5x² - 6 = 13x

⇒ 5x² - 13x - 6 = 0

So, D = (-13)² - 4 × 5 × (-6) = 289

So, the roots will be real and distinct.

8) x² - x = 3(x + 7)

⇒ x² - 4x - 21 = 0

It has D = (-4)² - 4 × 1 × (-21) = 100

So, the roots will be real and distinct. (Answer)

6 0
3 years ago
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The boy walks at a constant speed V=3 m/s where V is his velocity
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Thus we conclude during 1 minute he travels :
60 seconds × 3 meters/second = 180 meters
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