3 years ago

For which values of P and Q does the following equation have infinitely many solutions? Px-37=Qx-37

Mathematics

1 answer:

Lyrx [107]3 years ago

4 0

Answer:

The equation has infinitely many solutions for any value of P and Q such that P=Q.

Step-by-step explanation:

Px - 37 = Qx - 37

Px - Qx - 37 = -37

x (P-Q) = 0

==> P-Q=0 ==> P=Q

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netineya [11]

Answer:

2x +21

Step-by-step explanation:

$log_{5} {5}^{(2x - 9)} + log_{3} {729}^{5} \\ \\ = log_{5} {5}^{(2x - 9)} + log_{3} {( {3}^{6} )}^{5} \\ \\ = log_{5} {5}^{(2x - 9)} + log_{3} { {3}}^{6 \times 5} \\ \\ = log_{5} {5}^{(2x - 9)} + log_{3} { {3}}^{30} \\ \\ =(2x - 9) log_{5} {5} + 30 log_{3} { {3}} \\ \\ = (2x - 9).1 + 30(1 )\\ ( \because \: log_{a} { {a}} = 1) \\ \\ = 2x - 9 + 30 \\ \\ = 2x +21$