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3 years ago

For which values of P and Q does the following equation have infinitely many solutions? Px-37=Qx-37

Mathematics

1 answer:

Lyrx [107]3 years ago

4 0

Answer:

The equation has infinitely many solutions for any value of P and Q such that P=Q.

Step-by-step explanation:

Px - 37 = Qx - 37

Px - Qx - 37 = -37

x (P-Q) = 0

==> P-Q=0 ==> P=Q

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Answer:

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Step-by-step explanation:

Equation of a given line is a + 4b = 0 or b = - $\frac{1}{4}a$

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Here slope of the line is ( $-\frac{1}{4}$ ).

Or tanθ = $\frac{(-1)}{4}$

This line coincides with the terminal side of the angle in standard position where cosθ > 0

Since tanθ = $\frac{\text{Height}}{\text{Base}}$

and sinθ = $\frac{\text{height}}{\txt{Hypotenuse}}$

Hypotenuse = $\sqrt{\text{height}^{2}+\text{Base}^{2}}$

= $\sqrt{(1^{2}+4^{2})}$

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Since tanθ is negative and cosθ > 0 that means θ lie in fourth quadrant.

Therefore, sinθ will be negative.

[ $\frac{-sin\theta}{+cos\theta}=-tan\theta$ ]

sinθ = - $\frac{1}{\sqrt{17}}$

= - $\frac{1}{\sqrt{17}}\times \frac{\sqrt{17} }{\sqrt{17}} = -\frac{\sqrt{17}}{17}$

Answer will be option A.

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Sedaia [141]

Answer:

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Step-by-step explanation:

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