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Bingel [31]
3 years ago
9

School is canceled tomorrow or we are going hiking.​

Mathematics
2 answers:
Alex787 [66]3 years ago
8 0

Answer:

nice

Step-by-step explanation:

slega [8]3 years ago
3 0

Answer:

School is canceled tomorrow so we are going for hiking

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Here is another easy question to answer: What is the mean of the data sets {41,19,29,12,49,30}, {28,22,10,30,15}, {49,24,18,53,3
Grace [21]

Answer:

Data set A {41,19,29,12,49,30} = 30

Data set B {28,22,10,30,15} = 21

Data set C{49,24,18,53,38} = 36.4

Step-by-step explanation:

Data set A {41,19,29,12,49,30} =

Mean = Sum of terms/ number of terms

Number of term = 6

Mean = 41 + 19 + 29 + 12 + 49 + 30/ 6

= 180/6 = 30

Data set B {28,22,10,30,15} =

Mean = Sum of terms/ number of terms

Number of term = 5

Mean = 28 + 22 + 10 + 30 + 15/ 5

= 105/5 = 21

Data set C{49,24,18,53,38} =

Mean = Sum of terms/ number of terms

Number of term = 5

Mean =49 + 24 + 18 + 53 + 38/ 5

= 182/5 = 36.4

7 0
3 years ago
Sasha and Mona practiced swimming every day. They increased the number of minutes of swimming every week as described below: Sas
Lemur [1.5K]
I think Sasha's number increased by a fixed number and Mona's increased in a fixed number (by the way my mom's name is mona)

8 0
3 years ago
Determine if the given side lengths could be used to form a unique triangle, many different triangles, or no triangles.
miv72 [106K]

Answer:

no triangles

Step-by-step explanation:

As we know the basic rule to form a triangle is that the sum of the two sides must be greater than the third one.

Given that:

4 m, 5.1 m, 12.5 m

We have: 4 m + 5.1 m = 9.1 m < 12.5 m

So no triangles can be formed.

3 0
4 years ago
Read 2 more answers
If H is the circumcenter of triangle BCD, find each measure. CD, CE, HD, GD, HG, HF
Levart [38]

Answer:

H is the circumcenter of triangle BCD

  • CD = 2FD = 2*32 = 64
  • CE = BE = 26
  • HD = HC = 33
  • GD = 1/2BD = 1/2(58) = 29
  • HG = √HD ²-GD² = √33²-29² = 2√62 ≈ 15.75
  • HF = √HD ²-FD² = √33²-32² =√65 ≈ 8.06
7 0
3 years ago
Errors in an experimental transmission channel are found when thetransmission is checked by a certifier that detects missing pul
irina1246 [14]

Answer:

As shown below

Step-by-step explanation:

Given that when X denotes the errors in an experimental transmission channel, when checked by a certifier that detects missing pulses. follows the cumulative density function as given below:

F(x) = 0, 0

(a) P(X \leq  4) =F(4) = 0.9\\(b) P(X > 7)=1-F(8) = 0\\(c) P(X \leq  5)=F(6) = 0.9 \\(d) P(X> 4)=1-F(4)=1-0.9=0.1 \\(e) P(X \leq  2)=F(3) = 0.7

6 0
4 years ago
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