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Alekssandra [29.7K]
3 years ago
6

Y=-1 Y=2x-7 hsbdhdhhdhdjdjdjfjjfjfjffj

Mathematics
1 answer:
Molodets [167]3 years ago
6 0
2(-1)-7 first multiply 2(-1) which is simply -2, then subtract -2 by -7 which is 5. Sounds weird but you'll learn it in the future

Hope this helps:)
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PLEASE LOOK AT PHOTO! WHOEVER ANSWERS CORRECTLY I WILL MARK BRAINIEST!!
marissa [1.9K]

Answer:

53°

Step-by-step explanation:

It is given that the total measurement of the two angles combined would equate to 116°.

It is also given that m∠WXY is 10° more then m∠ZXY.

Set the system of equation:

m∠1 + m∠2 = 116°

m∠1 = m∠2 + 10°

First, plug in "m∠2 + 10" for m∠1 in the first equation:

m∠1 + m∠2 = 116°

(m∠2 + 10) + m∠2 = 116°

Simplify. Combine like terms:

2(m∠2) + 10 = 116

Next, isolate the <em>variable</em>, m∠2. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 10 from both sides of the equation:

2(m∠2) + 10 (-10) = 116 (-10)

2(m∠2) = 116 - 10

2(m∠2) = 106

Next, divide 2 from both sides of the equation:

(2(m∠2))/2 = (106)/2

m∠2 = 106/2 = 53°

53° is your answer.

~

8 0
2 years ago
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Answer:

Answer is C.

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Answer:

\large\boxed{x=\dfrac{1}{2}}

Step-by-step explanation:

\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\\\\\text{Domain:}\ x-4\neq0\ \wedge\ x+4\neq0\\\\x\neq4\ \wedge\ x\neq-4\\\\D:x\in\mathbb{R}-\{-4,\ 4\}

\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\qquad\text{cross multiply}\\\\(x+3)(x+4)=(x-4)(x-5)\qquad\text{use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(x)(x)+(x)(4)+(3)(x)+(3)(4)=(x)(x)+(x)(-5)+(-4)(x)+(-4)(-5)\\\\x^2+4x+3x+12=x^2-5x-4x+20\qquad\text{combine like terms}\\\\x^2+(4x+3x)+12=x^2+(-5x-4x)+20\\\\x^2+7x+12=x^2-9x+20\qquad\text{subtract}\ x^2\ \text{from both sides}\\\\7x+12=-9x+20\qquad\text{subtract 12 from both sides}\\\\7x=-9x+8\qquad\text{add}\ 9x\ \text{to both sides}\\\\16x=8\qquad\text{divide both sides by 16}\\\\x=\dfrac{8}{16}\\\\x=\dfrac{8:8}{16:8}\\\\x=\dfrac{1}{2}\in D

7 0
3 years ago
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