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4 years ago

What is the equation of the line in slope-intercept form? 12 points plz help!!!

Mathematics

1 answer:

Art [367]4 years ago

6 0

Answer: $y=-2x-4$

Step-by-step explanation:

The slope-intercept form of the line is:

$y=mx+b$

Where m is the slope and b the intersection with the y-axis.

You can see in the graph that line intersect the y-axis at $y=-4$ , then:

$b=-4$

Choose two points and substitute them into the formula for calculate the slope. This is:

$m=\frac{y_2-y_1}{x_2-x_1}$

Let's pick the points (-4,4) and (-6,8). The the slope is:

$m=\frac{4-8}{-4-(-6)}=\frac{-4}{2}=-2$

Substituting into the equation, you get:

$y=-2x-4$

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Evaluate the expression: 0.5f - 2.3g where f = 12 and g = 2

m_a_m_a [10]

Answer:

1.4

Step-by-step explanation:

0.5f-2.3g where f=12 and g=2

substitute 12 in for f and 2 in for g and solve

0.5(12)-2.3(2)

6-4.6=1.4

4 0

3 years ago

Read 2 more answers

A ladder is 12 metres long . It leans against a wall with one end on the ground 7 metres from the wall. The other end just reach

MissTica

Answer:

window sill height =9.75 meters

Step-by-step explanation:

Ladder^2=height^2+length^2

12^2=height^2+7^2

144=height^2+49

height^2=144-49=95

height=9.75

6 0

3 years ago

Can someone please help me with this geometry homework?

Leno4ka [110]

The distances between the two points, in units, are given as follows:

7. $\sqrt{2}$

8. $2\sqrt{17}$

9. $3\sqrt{2}$

10. $3\sqrt{5}$

The midpoints are given as follows:

11. (7,-4.5).

12. (2,4).

13. (7,0.5).

14. (5.5,-1.5).

<h3>What is the distance between two points?</h3>

Suppose that we have two points, $(x_1,y_1)$ and $(x_2,y_2)$ . The distance between them is given by:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For item 7, the points are (-3,-2) and (-4,-3), hence the distance is:

$D = \sqrt{(-4 + 3)^2 + (-3 + 2)^2} = \sqrt{2}$

For item 8, the points are (-3,1) and (5,3), hence the distance is:

$D = \sqrt{(5 + 3)^2 + (3 - 1)^2} = \sqrt{68} = 2\sqrt{17}$

For item 9, the points are (-3,0) and (0,-3), hence the distance is:

$D = \sqrt{(0 + 3)^2 + (-3 - 0)^2} = \sqrt{18} = 3\sqrt{2}$

For item 10, the points are (1,-2) and (4,4), hence the distance is:

$D = \sqrt{(4 - 1)^2 + (4 + 2)^2} = \sqrt{45} = 3\sqrt{5}$

<h3>What is the midpoint concept?</h3>

The midpoint between two points is the halfway point between them, and is found using the mean of the coordinates.

Hence, for item 11, the midpoint is given by:

[0.5(9 + 5), 0.5(1-10)] = (7,-4.5).

For item 12, the midpoint is given by:

[0.5(-5 + 9), 0.5(7 + 1)] = (2,4).

For item 13, the midpoint is given by:

[0.5(9 + 5), 0.5(9 - 8)] = (7,0.5).

For item 14, the midpoint is given by:

[0.5(10 + 1), 0.5(4 - 7)] = (5.5,-1.5).

More can be learned about the distance between two points at brainly.com/question/18345417

#SPJ1

8 0

2 years ago

Identify the percent of change as an increase or decrease. Then find the percent of change. Round to the nearest tenth of a perc

bazaltina [42]

I'll do the first two problems to get you started. All problems shown will use the same formula.

===========================================

Problem 4

The formula to use is

C = 100*(B-A)/A

where

A = old value

B = new value

C = percent change

In this case, A = 12 and B = 36, so

C = 100*(B-A)/A

C = 100*(36-12)/12

C = 100*(24/12)

C = 100*2

C = 200%

We have a 200% increase. It is an increase because the value of C is positive.

===========================================

Problem 5

Use the same formula as in the previous problem. This time,

A = 75 is the old value

B = 25 is the new value

C = 100*(B-A)/A

C = 100*(25-75)/75

C = 100*(-50/75)

C = 100*(-2/3)

C = -66.6667%

C = -66.7%

The value of C is negative, so we have a percent decrease of roughly 66.7%

8 0

3 years ago

Determine whether the following relation represent a function<br>

Bogdan [553]

Answer:

Step-by-step explanation:

It does not pass the vertical line test; two points have the same input and different outputs, and one input can only have one output.

8 0

3 years ago