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Murrr4er [49]
4 years ago
8

A pound is approximately 0.45 kilogram. A person weighs 87 kilograms. What is the persons weight, in pounds, when expressed to t

he correct number of significant figures.
Chemistry
1 answer:
pishuonlain [190]4 years ago
7 0
To work it out you’d go

87 ÷ 0.45
= 193.333… lbs

i don’t know how many significant figures you have to do but if it’s 3 significant figures then the answer is 193lbs

lbs = pounds
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Identify the missing daughter nucleus in the β– emission decay of 106ru below.
kotykmax [81]
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6 0
3 years ago
Which identifies an oxidation-reduction reaction?
Strike441 [17]

Answer:

Explanation:

The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄  →  Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is  also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

Oxidizing agents:

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8 0
4 years ago
How many moles of Aluminum are produced when34.2 g of alumina are broken down through the process of electrolysis
Elan Coil [88]

Answer:

0.670 mol

Explanation:

Step 1: Write the balanced reaction for the decomposition of alumina

2 Al₂O₃ ⇒ 4 Al + 3 O₂

Step 2: Calculate the moles corresponding to 34.2 g of Al₂O₃

The molar mass of Al₂O₃ is 101.96 g/mol.

34.2 g × 1 mol/101.96 g = 0.335 mol

Step 3: Calculate the moles of Al produced from 0.335 moles of Al₂O₃

The molar ratio of Al₂O₃ to Al is 2:4.

0.335 mol Al₂O₃ × (4 mol Al/2 mol Al₂O₃) = 0.670 mol Al

6 0
3 years ago
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