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Tems11 [23]
3 years ago
14

What moon phases would this be and why?

Chemistry
1 answer:
LenaWriter [7]3 years ago
7 0
Its been a long time since ive done this stuff but this chart used to help me a lot

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How many moles of iron are in 50.0g of iron? How many iron atoms are in 59.0g of iron?
Julli [10]

Answer:

50.0 \div 59.0 = 10

right

7 0
3 years ago
Calculate AH°rxn from AH°7 values (use table in textbook appendix) a) Cl2 (g) + 2 Na (s) -› 2 NaCl (s) EITHER -411.1kJ/mol b) 2
MrMuchimi

To find AH°rxn, we use the following equation:

What we're going to do is to sum the enthalpy of the products and then substract with the enthalpy of the reactives:

As you can see, we need to multiply by the coefficients of the reaction.

Now, just replace the values of the table:

So the answer is -822.2kJ/mol.

For b:

Now, just replace the values of the table:

The answer for b is -1036kJ/mol.

4 0
1 year ago
____is not a resource that can be used to help meet our energy needs
Bezzdna [24]
I believe the answer to this is A. 
7 0
3 years ago
How many moles of NaCl are created as a result of decomposing 12 grams of NaClO3? (molar mass of Na=23, Cl=35, O=16)
Harman [31]

Answer: 0.113 moles of NaCl are created as a result of decomposing 12 grams of NaClO_3.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}   

\text{Moles of} NaClO_3=\frac{12g}{106.5g/mol}=0.113moles

The balanced chemical equation for decomposition of NaClO_3 is:

2NaClO_3\rightarrow 2NaCl+3O_2  

According to stoichiometry :

2 moles of NaClO_3 give = 2 moles of NaCl

Thus 0.113 moles of NaClO_3 give =\frac{2}{2}\times 0.113=0.113moles  of NaCl

Thus 0.113 moles of NaCl are created as a result of decomposing 12 grams of NaClO_3.

8 0
3 years ago
What is the empirical formula for c12h24o6? what is the empirical formula for c12h24o6? ch2o cho c2h5o c2h4o cho2?
stira [4]

Empirical formula: The formula consist of proportions of the elements which is present in the compound or the simplest whole number ratios of atoms.

Now, molecular formula is equal to the product of n (ratio) and empirical formula.

Molecular formula = n\times empirical formula    (1)

molecular formula =C_{12}H_{24}O_{6} (given)

Since, 6 is the smallest subscript in above molecular formula to get the simpler whole number of atoms. Therefore, divide all the subscripts i.e. number of carbon atoms (12), number of hydrogen atoms (24) and number of oxygen atoms (6) by 6.

empirical formula becomes C_{2}H_{4}O

Thus, according to the formula (1)

C_{12}H_{24}O_{6} = 6\times C_{2}H_{4}O

Hence, empirical formula of given molecular formula is C_{2}H_{4}O


4 0
3 years ago
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