Answer:
∆t(f) = 49.755C
Explanation:
Freezing point is defined as the point in which a liquid changes from liquid to solid state. Therefore, to calculate the freezing point of aqueous solution of propanol
∆t = k × I × m
Where k is cryscopic constant =
I = vant Hoff factor = 2
M = molar concentration = 12.25m
∆t (f) = 1.9 × 12.25 × 2 = 49.755C
3.84 - 1.43 = 2.41
2.41g of table sugar
% mass = ( (mass of element) / (total mass) ) * 100
% mass = (2.41 / 3.84) * 100
% mass = (0.6276) * 100
% mass = 62.76
62.76%
Answer:
It changed by -7 degrees Celsius.
Explanation:
Answer : Cadmium sulfide (CdS) precipitate is formed.
Explanation :
When the sodium sulfide,
is mixed with cadmium sulfate,
then cadmium sulfide precipitate and sodium sulfate,
is formed. The cadmium sulfide is insoluble in hot and cold water but sodium sulfate is soluble in water.
The balanced chemical reaction will be,

This reaction is an example of double displacement reaction in which the cation and anion of the two reactants exchange their places to give two new products.
This is a chemical reaction where the two clear solutions mixed to produce a bright yellow colored precipitate of cadmium sulfide.
Ice because the molecules have less movement in solids