One worker<span> produces an average of 84 units per </span>day<span> with a street </span>What is the probability<span> that in any </span>single day worker 1 will outproduce worker 2<span>? A) 0.1141.
</span>
Answer, factory worker productivity<span> is </span>normally distributed<span>. </span>One worker produces<span> an </span>average<span> of 75 </span>units per day<span> with a standar, day with a </span>standard deviation<span> of 20. </span>Another worker produces<span> at an </span>average rate<span> of 65 </span><span>per day.
</span>
ZERO
as it is eventually multiplied by 0
R is the rate (10%)
C=20, begiing rate
T=time=8
so
h=20(1+0.10)^8
h=20(1.1)^8
h=42.8718
ronnd
$42.87
D is answer
Answer:
the answer is the question B!!
Step-by-step explanation:
Answer:
168.43524
Step-by-step explanation:
A=ah+bh+ch+1
2﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=7·6+7·6+7·6+1
2·﹣74+2·(7·7)2+2·(7·7)2﹣74+2·(7·7)2﹣74≈168.43524
