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yan [13]
3 years ago
5

An automobile with an initial speed of 5.13 m/s accelerates uniformly at the rate of 3.0 m/s2. Find the final speed of the car a

fter 4.9 s. Answer in units of m/s.
Physics
1 answer:
Digiron [165]3 years ago
7 0

Answer:

Final velocity v=19.83 m/sec

Explanation:

We have given initial velocity u =5.13 m/sexc

Acceleration of automobile a=3m/sec^2

Time t =4.9 sec

We have to find the final velocity v

According to first law of motion v = u+at ,here v is the final velocity , a is acceleration and t is time

So v=5.13+3\times 4.9=19.83m/sec

So the final velocity is 19.83 m/sec

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An object of mass m is traveling in a circle with centripetal force f c. If the velocity of the object is v, what is the radius
Gnom [1K]

Answer:

r = mv^2/ Fc

Explanation:

Got it right

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3 years ago
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8 0
3 years ago
A uniform thin rod of mass ????=3.41 kg pivots about an axis through its center and perpendicular to its length. Two small bodie
vivado [14]

Answer:

The length of the rod for the condition on the question to be met is L  =  1.5077 \ m

Explanation:

The  Diagram for this  question is  gotten from the first uploaded image  

From the question we are told that

          The mass of the rod is M  =  3.41 \ kg

           The mass of each small bodies is  m =  0.249 \ kg

           The moment of inertia of the three-body system with respect to the described axis is   I  =  0.929 \ kg \cdot  m^2

             The length of the rod is  L  

     Generally the moment of inertia of this three-body system with respect to the described axis can be mathematically represented as

        I =  I_r + 2 I_m

Where  I_r is the moment of inertia of the rod about the describe axis which is mathematically represented as  

        I_r  =  \frac{ML^2 }{12}

And   I_m the  moment of inertia of the two small bodies which (from the diagram can be assumed as two small spheres) can be mathematically represented  as

           I_m  =   m * [\frac{L} {2} ]^2 =  m*  \frac{L^2}{4}

Thus  2 *  I_m  =  2 *  m  \frac{L^2}{4}  = m  *  \frac{L^2}{2}

Hence

       I  =  M  *   \frac{L^2}{12}  +  m  * \frac{L^2}{2}

=>   I  =    [\frac{M}{12}  + \frac{m}{2}] L^2

substituting vales  we have  

        0.929   =    [\frac{3.41}{12}  + \frac{0.249}{2}] L^2

       L  =  \sqrt{\frac{0.929}{0.40867} }

      L  =  1.5077 \ m

     

6 0
3 years ago
Near the earth's surface, the electric field in the open air has magnitude 150 N/c and is directed down towards the ground. If t
kati45 [8]

Hi there!

Using the equation for the electric field produced by an infinite sheet of charge:

E = \frac{\sigma}{2\epsilon_0}

E = Electric field strength (150 N/C)

σ = Surface charge density (? C/m²)

ε₀ = Permittivity of free space (8.8542× 10⁻¹² C²/Nm²)

We can rearrange the equation to solve for the surface charge density (charge per unit area)

E = \frac{\sigma}{2\epsilon_0}\\\\\sigma = 2E\epsilon_0\\\\\sigma = 2(150)(8.8542*10^{-12}) = \boxed{2.656 \times 10^{-9} \frac{C}{m^2}}

3 0
2 years ago
When the availability of resoures in an area is limited organisms may leave a population to move to an area with more resoures .
disa [49]

Answer:

Migration

Explanation:

Migration is the movement of organisms from one region or place of habitat to another region. Organisms migrate from one region to another to increase their rates of survival. Migration of organisms from one habitat to another may be due to unavailability of insufficiency of resources that are required for their survival.

6 0
4 years ago
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