What is the half-life of this radioactive isotope that decreases to one-fourth its original amount in 18 months?
1 answer:
You might be interested in
M = mass of aluminium = 1.11 kg
= specific heat of aluminium = 900
= initial temperature of aluminium = 78.3 c
m = mass of water = 0.210 kg
= specific heat of water = 4186
= initial temperature of water = 15 c
T = final equilibrium temperature = ?
using conservation of heat
Heat lost by aluminium = heat gained by water
M (
- T) = m
(T -
)
(1.11) (900) (78.3 - T) = (0.210) (4186) (T - 15)
T = 48.7 c
Answer:
λ = 470.66 nm
Explanation:
for bright fringe
D= distance between slit and screen
d= distance between the slits
for first order bright fringe m = 1,
for dark fringe,we have
Now to get the dark fringes at the same location we should have;
(706)D/d = (m + 1/2)λD/d
put m = 1
(1 + 1/2)λ = (706)
λ = 470.66 nm
Answer:
24 N
Explanation:
= mass of the cube =
Consider the three cubes together as one.
= mass of the three cubes together =
= acceleration of the combination = 2 ms⁻²
= Force applied on the combination
Using Newton's second law
= Force by the left cube on the middle cube
Consider the forces acting on left cube, from the force diagram, we have
