Ask question

Ask question

All categories

3 years ago

5

What is the half-life of this radioactive isotope that decreases to one-fourth its original amount in 18 months?

1 answer:

o-na [289]3 years ago

4 0

The half-life of this radioactive isotope is 9 months for it decreases to one-fourth its original amount in 18 months. Half-life means a certain length of time after which half of the amount of radioactive element has decayed.
Therefore, the half-life of this particular isotope is 18 months. After 18 months the isotope was at one-half, then another 18 months, the isotope was at one-fourth, which is 9 months where one-fourth is one-half of one half.

You might be interested in

A weight lifter applies an upward force of 1100 N while lowering a dumbbell

Paul [167]

Answer:

A

Explanation:

$work = force \times distance$

$work = 1100 \times 0.5$

$= 550 \: j$

hope it helped a lot

pls mark brainliest with due respect .

6 0

3 years ago

A proton is located at <3 x 10^-10> m. What is r, the vector from the origin to the location of the proton

Eduardwww [97]

Complete Question

A proton is located at <3 x 10^{-10}, -5*10^{-10} , -5*10^{-10}> m. What is r, the vector from the origin to the location of the proton

Answer:

The vector position is $\=r=$

Explanation:

From the question we are told that

The position of the proton is $m$

Generally the vector location of the proton is mathematically represented as

$\= r =$

So substituting values

$\=r=$

4 0

3 years ago

Unele rigle gradate au partea pe care sunt imprimante graditatiile in forma de pana. prezinta aceasta vreo importanta pentru mas

GrogVix [38]

Da ne ajuta pentru a putea citi corect lungimea ... coronită???

7 0

3 years ago

A car is traveling at 70 km/h. It then uniformly decelerates to a complete stop in 12 s. Find its acceleration ( in m/s2 ).

Yakvenalex [24]

Answer:

Acceleration will be $-1.620m/sec^2$

Explanation:

We have given initial speed of the car is 70 km/hr

We know that 1 km = 1000 m

And 1 hour = 3600 sec

So $70km/hr=70\times \frac{1000m}{3600sec}=19.444m/sec$

It is given that car stops in 12 sec

So final speed of the car v = 0 m/sec

Time t = 12 sec

From first equation of motion v = u+at

So $0=19.444+a\times 12$

$a=\frac{-19.444}{12}=-1.620m/sec^2$ ( negative sign indicates that speed of the car will constantly decrease )

5 0

3 years ago

Read 2 more answers

If Michael Jordan has a vertical leap of 1.29 meters, what is his take-off speed and his hang time (total time to move upwards t

evablogger [386]

(Hint: the time<span> to rise to the </span>peak<span>is one-half the </span>total hang-time<span>.).</span>

6 0

3 years ago