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BlackZzzverrR [31]
3 years ago
8

Arrange the following substances in order of decreasing magnitude of lattice energy.

Physics
2 answers:
kolbaska11 [484]3 years ago
5 0
The formula is F = ( q1 * q2 ) / r ^ 2 
<span>where: q is the individual charges of each ion </span>
<span>r is the distance between the nuclei </span>
<span>The formula is not important but to explain the relationship between the atoms in the compounds and their lattice energy. </span>

<span>From the formula we can first conclude that compounds of ions with greater charges will have a greater lattice energy. This is a direct relationship. </span>
<span>For example, the compounds BaO and SrO, whose ions' charges are ( + 2 ) and ( - 2 ) respectively for each, will have greater lattice energies that the compounds NaF and KCl, whose ions' charges are ( + 1 ) and ( - 1 ) respectively for each. </span>

<span>So Far: ( BaO and SrO ) > ( NaF and KCl ) </span>

<span>The second part required you find the relative distance between the atoms of the compounds. Really, the lattice energy is stronger with smaller atoms, an indirect relationship. </span>
<span>For example, in NaF the ions are smaller than the ions in KCl so it has a greater lattice energy. Because Sr is smaller than Ba, SrO has a greater lattice energy than BaO. </span>

<span>Therefore: </span>
<span>Answer: SrO > BaO > NaF > KCl </span>
qwelly [4]3 years ago
3 0

The following substances in order of decreasing magnitude of lattice energy are as follows: SrO > BaO > NaF > KCl

<h3>Explanation: </h3>

Ionic compounds are more stable because their have an electrostatic force between the two opposite ions. After the formation of ions, they combine together to form the ionic compound. The lattice energy or lattice enthalpy is  the energy released in this process. It means the energy released when a cation and a anion combine together to form one mole of an ionic compound that known as the lattice energy or lattice enthalpy.

To calculation of lattice energy we can done by using Hess’s law (or called Born Haber cycle).  Hess' law of constant or the heat summation, also known as Hess' law is a relationship in physical chemistry that named after Germain Hess. Hess's Law states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes.

The formula is F = \frac{ ( q1 * q2 ) }{ r ^ 2 }

The compounds BaO and SrO, have ions' charges ( + 2 ) and ( - 2 ) respectively will have greater lattice energies that the compounds NaF and KCl that have charges ( + 1 ) and ( - 1 ) respectively

( BaO and SrO ) > ( NaF and KCl )

In NaF, the ions are smaller than the KCl ions so it has the greater lattice energy. Sr is smaller than Ba therefore SrO has a greater lattice energy than BaO.

Therefore SrO > BaO > NaF > KCl

Learn more about   substances brainly.com/question/10907082

#LearnWithBrainly

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During a rodeo, a clown runs 7.7 m north, turns 49.9 degrees east of north, and runs 6.4 m. Then after waiting for the bull to c
IRINA_888 [86]

During a rodeo, a clown runs 7.7 m north, turns 49.9 degrees east of north, and runs 6.4 m. Then after waiting for the bull to come near, the clown turns due east and runs 19.8 m to exit the arena. The magnitude of the clown’s displacement is 27 m.

<u>Explanation: </u>

As the clown is running in the north direction for about 7.7 m and then he turns 49.9 degrees east of north. In the east of north, he covers a distance of 6.4 m and then turns east to exit the arena after covering a distance of 19.8 m. Let’s have a simple diagram to easily understand the problem.

In first step, the clown runs 7.7 m in north direction, so the image will be  as in fig 1. Then he takes a direction of north east and covers a distance of 6.4 m, so the image will be modified as in fig 2. Then after the bull comes, he turns east and runs 19.8 m to exit the arena, so the image will be as in figure 3.

So, the extension of North line and the East line at a point shown as the dotted line in the above image, forms the total displacement as the hypotenuse of a right angled triangle. The extended dotted lines is nothing but the horizontal and vertical components of the angle 49.9 degree.

By using Pythagoras theorem, the total displacement can be found as

\text { Total displacement }=\sqrt{(o p p)^{2}+(a d j)^{2}}

\text { Distance covered by the clown in east direction }=(6.4 \times \cos 49.9)+19.8=23.9 \mathrm{m}

Similarly, the adjacent side of this imaginary triangle is the distance covered by the clown in the North direction.

\text { Distance covered by the clown in north direction }=6.4 \sin 49.9+7.7=12.6 \mathrm{m}

Thus, the total displacement covered by the clown is

\text { Total displacement }=\sqrt{(23.9)^{2}+(12.6)^{2}}=\sqrt{571.21+158.76}=\sqrt{729.97}=27 \mathrm{m}

Thus, the total displacement by the clown is 27 m.

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if an average cloud has a density of 0.5 g/m3 and has a volume of 1,000,000,000 m3,what is the weight of an average cloud
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If you have (1 x 10⁹) cubic meters of volume, and 1/2 gram of mass
in each cubic meter, then you have

          (1/2 x 10⁹) grams = (5 x 10⁸) grams = (5 x 10⁵) kilograms of mass . 

On Earth, that mass weighs  4,900,000 newtons .

                                            (about  1,102,300 pounds)

                                            (about  551 tons)

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What is the relationship between dominant and recessive genes
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3 years ago
The parallel plates in a capacitor, with a plate area of 8.00 cm2 and an air-filled separation of 2.70 mm, are charged by a 8.70
MrRa [10]

Answer:

a)  ΔV₁ = 21.9 V, b) U₀ = 99.2 10⁻¹² J, c) U_f = 249.9 10⁻¹² J,  d)  W = 150 10⁻¹² J

Explanation:

Let's find the capacitance of the capacitor

         C = \epsilon_o \frac{A}{d}

         C = 8.85 10⁻¹² (8.00 10⁻⁴) /2.70 10⁻³

         C = 2.62 10⁻¹² F

for the initial data let's look for the accumulated charge on the plates

          C = \frac{Q}{\Delta V}

          Q₀ = C ΔV

           Q₀ = 2.62 10⁻¹² 8.70

           Q₀ = 22.8 10⁻¹² C

a) we look for the capacity for the new distance

          C₁ = 8.85 10⁻¹² (8.00 10⁻⁴) /6⁴.80 10⁻³

          C₁ = 1.04 10⁻¹² F

       

          C₁ = Q₀ / ΔV₁

          ΔV₁ = Q₀ / C₁

          ΔV₁ = 22.8 10⁻¹² /1.04 10⁻¹²

          ΔV₁ = 21.9 V

b) initial stored energy

          U₀ = \frac{Q_o}{ 2C}

          U₀ = (22.8 10⁻¹²)²/(2  2.62 10⁻¹²)

          U₀ = 99.2 10⁻¹² J

c) final stored energy

          U_f = (22.8 10⁻¹²) ² /(2  1.04 10⁻⁻¹²)

          U_f = 249.9 10⁻¹² J

d) the work of separating the plates

as energy is conserved work must be equal to energy change

          W = U_f - U₀

          W = (249.2 - 99.2) 10⁻¹²

          W = 150 10⁻¹² J

note that as the energy increases the work must be supplied to the system

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What's the real power of a purely resistive circuit in which the RMS voltage measures 80 volts and the RMS current measures 5 am
Nat2105 [25]

Answer:

D.400 watt

Explanation:

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<em>where</em><em> </em><em>Pave</em><em> </em><em>=</em><em> </em><em>average</em><em> </em><em>power</em><em> </em>

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<em>Vrms</em><em>=</em><em>RMS</em><em> </em><em>voltage</em>

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