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3 years ago

Arrange the following substances in order of decreasing magnitude of lattice energy.

2 answers:

5 0

The formula is F = ( q1 * q2 ) / r ^ 2
where: q is the individual charges of each ion 
r is the distance between the nuclei 
The formula is not important but to explain the relationship between the atoms in the compounds and their lattice energy. 

From the formula we can first conclude that compounds of ions with greater charges will have a greater lattice energy. This is a direct relationship. 
For example, the compounds BaO and SrO, whose ions' charges are ( + 2 ) and ( - 2 ) respectively for each, will have greater lattice energies that the compounds NaF and KCl, whose ions' charges are ( + 1 ) and ( - 1 ) respectively for each. 

So Far: ( BaO and SrO ) > ( NaF and KCl ) 

The second part required you find the relative distance between the atoms of the compounds. Really, the lattice energy is stronger with smaller atoms, an indirect relationship. 
For example, in NaF the ions are smaller than the ions in KCl so it has a greater lattice energy. Because Sr is smaller than Ba, SrO has a greater lattice energy than BaO. 

Therefore: 
Answer: SrO > BaO > NaF > KCl

qwelly [4]3 years ago

3 0

The following substances in order of decreasing magnitude of lattice energy are as follows: SrO > BaO > NaF > KCl

<h3>Explanation: </h3>

Ionic compounds are more stable because their have an electrostatic force between the two opposite ions. After the formation of ions, they combine together to form the ionic compound. The lattice energy or lattice enthalpy is the energy released in this process. It means the energy released when a cation and a anion combine together to form one mole of an ionic compound that known as the lattice energy or lattice enthalpy.

To calculation of lattice energy we can done by using Hess’s law (or called Born Haber cycle). Hess' law of constant or the heat summation, also known as Hess' law is a relationship in physical chemistry that named after Germain Hess. Hess's Law states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes.

The formula is $F = \frac{ ( q1 * q2 ) }{ r ^ 2 }$

The compounds BaO and SrO, have ions' charges ( + 2 ) and ( - 2 ) respectively will have greater lattice energies that the compounds NaF and KCl that have charges ( + 1 ) and ( - 1 ) respectively

( BaO and SrO ) > ( NaF and KCl )

In NaF, the ions are smaller than the KCl ions so it has the greater lattice energy. Sr is smaller than Ba therefore SrO has a greater lattice energy than BaO.

Therefore SrO > BaO > NaF > KCl

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Why is it that the two possible faults with inductors are short circuit and open circuit?

lukranit [14]

These are the most common type of faults not just inductors but also with other elements too like resistors,transformers, generators etc.
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3 years ago

A fisherman is fishing from a bridge and is using a "44.0-N test line." In other words, the line will sustain a maximum force of

vitfil [10]

Answer:

a) 4.485 kg b) 3.94 kg

Explanation:

since the maximum tension the line can stand is 44 N and for question a the speed is constant (acceleration must be zero since the velocity or speed is not changing), F(tension) = mass * acceleration due to gravity (g) .

44 = m * 9.81m/s^2

m = 44/9.81 = 4.485kg

b) F(tension) = ma + mg ( where a is the acceleration of the body and g is the acceleration of the gravity)

44 = m (a +g)

44 = m (1.37 + 9.81)

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3 years ago

A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.060 m/s and acceleration -0.3

shusha [124]

Answer:

$x_2 = -2.3356$

$v = -1.384 \ m/s$

Explanation:

From the question we are told that

The initial position of the particle is $x_1 = 0.180 \ m$

The initial velocity of the particle is $u = 0.060 \ m/s$

The acceleration is $a = -0.380 \ m/s^2$

The time duration is $t = 3.80 \ s$

Generally from kinematic equation

$v = u + at$

=> $v = 0.060 + (-0.380 * 3.80)$

=> $v = -1.384 \ m/s$

Generally from kinematic equation

$v^2 = u^2 + 2as$

Here s is the distance covered by the particle, so

$(-1.384)^2 = (0.060)^2 + 2(-0.380)* s$

=> $s = -2.5156 \ m$

Generally the final position of the particle is

$x_2 = x_1 + s$

=> $x_2 = 0.180 + (-2.5156)$

=> $x_2 = -2.3356$

6 0

2 years ago

One way to heat a gas is to compress it. A gas at 3.0 atm at 27°C is compressed to three tenths of its original volume, and it r

-Dominant- [34]

Answer:

T =3227 °C

Explanation:

Given data:

P1 = 3.0 atm

T1 = 27 degree celcius

P2 = 35 atm

from ideal gas equation

PV/T=const

$\frac{P_1 V_1}{T_1} =\frac{P_2 V_2}{T_2}$

$\frac{3*V}{(27+273)}=\frac{35*V*10}{T}$

solving for T WE GET

[/tex]0.01V = \frac{350V}{T}[/tex]

T=3500K

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2 years ago

A toroid having a square cross section, 4.76 cm on a side, and an inner radius of 22.0 cm has 740 turns and carries a current of

Stels [109]

Answer:

a. $\beta_{in}=6.79x10^{-4}T$

b. $\beta_{out}=5.586x10^{-4}T$

Explanation:

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