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Alex Ar [27]
2 years ago
8

A rectangle has an area of 31.2 square millimeters and a heigt of 5.2 millimeters. What is the length of the base ​

Mathematics
1 answer:
Schach [20]2 years ago
6 0

Answer:

6 millimeters

Step-by-step explanation:

The formula for a rectangle is length * height = area.

Since we know the area and height, we can plug it in to the formula:

length * 5.2 = 31.2

So the length is just dividing 5.2 in 31.2 which gives 6 millimeters.  

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Carson bought a coat for 40% of the original price, then another 15% off the discounted price. If the coat originally cost $149,
irinina [24]
Answer: $75.99

Steps: 149×0.6= 89.4
Multiply 89.4×0.85= 75.99

Hope this helps ʕ•ᴥ•ʔ
5 0
3 years ago
A boat is heading towards a lighthouse, whose beacon-light is 139 feet above the
Novay_Z [31]

The horizontal distance between light house and boat is 1588.78 feet approximately.

The figure is given by,

Here, AB  = height of the lighthouse bacon light above the water = 139 feet

Now angle ACB = 5 degree

Let the horizontal distance of light house from the boat = BC = x feet

So by trigonometric function we get,

tan 5 = AB/BC

tan 5 = 139/x

x = 139/tan 5 = 1588.78 (approximately)

Hence the horizontal distance between light house and boat is 1588.78 feet approximately.  

To know more about Trigonometric Function refer to:

brainly.com/question/1143565

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5 0
1 year ago
Van purchased a DVD player on sale. The original selling price was
hammer [34]

Answer:

the first step is find the amount of money you saved

Step-by-step explanation:

171.50-145.12=26.38

26.38 / 171.5 = .154

15.4%

8 0
2 years ago
Given: BD bisects ABC. Auxiliary EA is drawn such that AE || BD. Auxiliary BE is an extension of BC
AnnZ [28]
The required proof is given in the table below:

\begin{tabular}{|p{4cm}|p{6cm}|} 
 Statement & Reason \\ [1ex] 
1. $\overline{BD}$ bisects $\angle ABC$ & 1. Given \\
2. \angle DBC\cong\angle ABD & 2. De(finition of angle bisector \\ 
3. $\overline{AE}$||$\overline{BD}$ & 3. Given \\ 
4. \angle AEB\cong\angle DBC & 4. Corresponding angles \\
5. \angle AEB\cong\angle ABD & 5. Transitive property of equality \\ 
6. \angle ABD\cong\angle BAE & 6. Alternate angles
\end{tabular}
\begin{tabular}{|p{4cm}|p{6cm}|}
7. \angle AEB\cong\angle BAE & 7. Transitive property of equality \\
8. \overline{EB}\cong\overline{AB} & 8. From 7. $\Delta ABE$ is isosceles \\
9. EB = AB & 9. De(finition of congruence \\ 10. $\frac{AD}{DC}=\frac{EB}{BC}$ & 10. Triangle proportionality theorem \\
11. $\frac{AD}{DC}=\frac{AB}{BC}$ & 11. Substitution Property of equality \\[1ex] 
\end{tabular}

7 0
3 years ago
Read 2 more answers
Can someone please help I will give you 30 points and brainliest if the answer is right also no links please
Zolol [24]

Answer:

B: BC ≅EC

Step-by-step explanation:

You know that the two angles starting in C are congruent (they're opposite by vertex C).

Given that the B angle and the E angle are congruent, in order for the two triangles to be congruent by A(ngle)S(ide)A(ngle) you want the side inbetween to be congruent. That is BC and EC. Option B

5 0
2 years ago
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