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3 years ago

I don’t pay attention in class

Mathematics

2 answers:

zvonat [6]3 years ago

8 0

Pay attention then lol.

Elanso [62]3 years ago

8 0

Step-by-step explanation:

All the angles in a triangle add up to 180 degrees

x-22 + 3x+19 + x-17 = 180

x+3x+x-22+19-17=180

5x - 20=180

5x=180+20

5x=200

5x/5=200/5

x=40

Angle A= x-22

Substitute x in the question

= 40 - 22

=18

Therefore angle A is 18 degrees

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Solve 0= 2t^3-21t^2+ 40t

sukhopar [10]

$0=2t^3-21^2+40t$
switch sides
$2t^3-21t^2+40t=0$
solve factoring
$t(t-8)(2t-5)=0$
using the zero factor principle
$t=0
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solve
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solve
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3 years ago

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Find the product. (-2x^2 )^3 ·3 x

jeka94

Assignment: $\bold{Solve \ \left(-2x^2\right)^3\cdot \:3x}$

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Answer: $\boxed{\bold{-24x^7}}$

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Explanation: $\downarrow\downarrow\downarrow$

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[ Step One ] Rewrite $\bold{\left(-2x^2\right)^3}$

$\bold{-2^3\left(x^2\right)^3}$

[ Step Two ] Rewrite Equation

$\bold{-2^3\cdot \:3x^6x}$

[ Step Three ] Apply Exponent Rule

Note: $\bold{Exponent \ Rule \ \:a^b\cdot \:a^c=a^{b+c}: \ x^6x=\:x^{6+1}=\:x^7}$

$\bold{-2^3\cdot \:3x^7}$

[ Step Four ] Refine

$\bold{-24x^7}$

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