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Reptile [31]
3 years ago
5

Consider the following matrix. A = 1 k 2 −5 6 1 Assume that the matrix is the augmented matrix of a system of linear equations.

(a) Determine the number of equations and the number of variables.
Mathematics
1 answer:
DedPeter [7]3 years ago
7 0

Answer: 2 eqautions and 2 variables

Step-by-step explanation: To solve linear systems, the equations can be represented by an augmented matrix.

To create one, each row represents the coeficients and constants (the numbers after the equal sign) from one equation and each column exhibit all the coeficients for a single variable. This means that the first column of an augmented matrix is for the coeficients of the x-terms, the second for the coeficients of the y-terms, the third column for the z-terms and so on.

For this question:

A = \left[\begin{array}{ccc}1&k&2\\-5&6&1\end{array}\right] or it can be written as

x + ky = 2

-5x + 6y = 1

Thus, the system has 2 equations and 2 variables.

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The difference of two numbers is 16 the greater number is five less than four times a small number find the two numbers
Elis [28]

Answer:

The numbers are 23 and 7  

Step-by-step explanation:

1. Set up the equations

   Let x = the greater number

  and y = the smaller number. Then

(1) x - y = 16

       4y = 4 times the smaller number and

  4y - 5 = 5 less than 4 times the smaller number. Then

(2)     x = 4y - 5

You have a system of two equations:

\begin{cases}(1) & x - y = 16\\(2) & x = 4y - 5\end{cases}

2. Solve the equations

\begin{array}{lrcll}(3) & 4y - 5 - y & = & 16 &\text{Substituted (2) into (1)}\\& 3y - 5 & = & 16 &\text{Simplified}\\ & 3y & = & 21 &\text{Added 5 to each side}\\(4) &y & = & \mathbf{7} &\text{Divided each side by 3} \\& x - 7 & = & 16 & \text{Substituted (4) into (1)}\\& x& = & \mathbf{23} & \text{Added 7 to each side}\\\end{array}

The larger number is 23; the smaller number is 7.

3. Check

\begin{array}{rclcrcl}23 - 7& = & 16 & \qquad &23&=&4(7) - 5\\16 & = & 16 & \qquad &23& = &28 - 5\\&&& \qquad &23& = &23\\\end{array}

OK.

3 0
3 years ago
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