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never [62]
2 years ago
6

Are the given lines parallel? Explain X=-1, and y=2

Mathematics
2 answers:
german2 years ago
5 0
No they would be intersecting. x=-1 is a vertical line down the x axis on -1. y=2 is a horizontal line at 2 on the y axis.
Zielflug [23.3K]2 years ago
5 0

Hi! Your problem will be explained in the explanation section.

Furthermore, your answer is No, the given lines are not parallel.

Why? See below! Questions about my answer and explanation can be asked through comments! :)

Step-by-step explanation:

Hi there! Today I will be explaining these things which may benefit you.

  • Parallel Line
  • Perpendicular Line
  • Horizontal and Vertical Line

You might have known or heard these lines somewhere. <em>But what are they?</em>

<u>Parallel</u>

Parallel Lines are lines that do not intercept each others. They are same lines except they have distance. I think you might be confusing if I keep explaining. Let's look at an attachment instead. Please see <u>the first attachment</u> for how do parallel lines look like.

<u>Perpendicular</u>

Perpendicular Lines are lines that intercept each others. Both lines intercepting each others create a right angle around the interception. See <u>the second attachment</u> for how do perpendicular lines look like.

Next things are going to be main topic for our problem. <em>What is the difference between graph of x = -1 and y = 2?</em>

In the coordinate plane, graph of x-coordinate would be a straight vertical line because x = -1 isn't given any ranges. Therefore, x = -1 would have range as real number.

Similar to y = 2. y = 2 isn't given any domains. Therefore, y = 2 would have domain as real number and have a horizontal line graph.

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In the figure, PQ is parallel to RS. The length of RP is 2 cm; the length of PT is 18 cm; the length of QT is 27 cm. What is the
Sidana [21]

Step 1    

<u>Find the value of TS</u>

we know that

if PQ is parallel to RS. then triangles TRS and TPQ are similar

so

\frac{TR}{TP} =\frac{TS}{QT}

solve for TS

TS =\frac{TR*QT}{TP}

we have

RP=2\ cm\\TP=18\ cm\\QT=27\ cm

TR=TP+RP\\TR=18+2=20\ cm

substitute

TS =\frac{20*27}{18}  

TS =30\ cm

Step 2

<u>Find the value of SQ</u>

we know that

SQ=TS-QT

we have

TS =30\ cm

QT=27\ cm

substitute

SQ=30\ cm-27\ cm=3\ cm

therefore

<u>the answer is</u>

the value of SQ is 3\ cm

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