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kvasek [131]
3 years ago
13

A vertical plane passes through a pyramid that has a horizontal base. which of the following can be produced from the intersecti

on of the vertical plane and pyramid
Mathematics
1 answer:
Inessa [10]3 years ago
4 0

Answer with explanation:

Pyramid and Plane both are three dimensional shapes.

Pyramid is a three dimensional shape having base any polygon and other faces as triangles.

The base of pyramid is horizontal.

1. If lower  base is a Square,or rectangle or any other parallelogram

And, then , plane cuts the pyramid vertically

It will be also, a three dimensional shape ,resembling a triangular cross section in three dimension.

Triangle is appropriate choice.

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7.675 inches of rain was the total amount in the two weeks
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If $5000 is invested at an interest rate of 3.396 compounded monthly for 10 years, what would be the balance in the account
saul85 [17]

Answer: D

Step-by-step explanation:

Months = 12 x 10 = 120months

100%+3.396%=103.396% / 100 = 1.03396

5000 X (1.03396)^120 = 275054.36

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4 years ago
The theoretical probability for rain is 1/5. the experimental probability for rain is?
Ierofanga [76]

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1/6. Hope this helps

Step-by-step explanation:

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3 years ago
Show that the following argument with hypotheses on lines 1–2 and conclusion on line c is
Sonja [21]

Answer:

Step-by-step explanation:

p \Rightarrow q \equiv (\neg p \vee q) [logical equivalence]

\neg (q \vee r) \equiv (\neg q \wedge \neg r) [morgan laws]

if (\neg q \wedge \neg r) is true, then \neg q is true and \neg r is too.

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7 0
3 years ago
NEED MATH HELP QUICK!
Korolek [52]

Answer:

Minimum = 14

Q_1=23

Median = 32

Q_3=49

Maximum = 65

Step-by-step explanation:

<u>Step 1: </u>Put your numbers in ascending order (from smallest to largest). For this particular data set, the order is

14, 18, 28, 29, 32, 44, 48, 50, 65

<u>Step 2:</u> Find the minimum and maximum for your data set. Now that your numbers are in order, this should be easy to spot.

Minimum = 14

Maximum = 65

<u>Step 3: </u>Find the median. The median is the middle number. The middle number in your list is 32, so

Median = 32

<u>Step 4: </u>Place parentheses around the numbers above and below the median.

(14, 18, 28, 29), 32, (44, 48, 50, 65)

<u>Step 5: </u>Find Q1 and Q3. Q1 can be thought of as a median in the lower half of the data, and Q3 can be thought of as a median for the upper half of data.

First quartile

\bf{Q_1=\dfrac{18+28}{2}=\dfrac{46}{2}=23}

Third quartile

\bf{Q_3=\dfrac{48+50}{2}=\dfrac{98}{2}=49}

<u>Step 6:</u> Write down your summary found in the above steps.

Minimum = 14

Q_1=23

Median = 32

Q_3=49

Maximum = 65

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4 years ago
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