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3 years ago

8

Emma had 154 stamps and her sister had 248 stairs they come binders collections and put the stands in an album if they want to p

ut a stamp on each page about how many pages what they need?

1 answer:

elena55 [62]3 years ago

6 0

First. multiply then divide the product by 248

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178.

If number CLXXVIII is within to text or sentence it should be read in its equivalent in arabic numbers, in this case 178.

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3 years ago

Ten less then quotient of a number and 3 is 8

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Answer:The answer is 6

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2 questions in one.<br> Help?..

daser333 [38]

Answer:

2. 3

3. 4^45

Step-by-step explanation:

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3 years ago

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Gala2k [10]

<h3>Total snow fall for three days is 8.75 inches</h3>

<em><u>Solution:</u></em>

Given that,

Snow fell over the past three days

$First\ day = 3\frac{2}{4}\ inches = \frac{14}{4}\ inches\\\\Second\ day = 3\frac{2}{4}\ inches = \frac{14}{4}\ inches\\\\Third\ day = 1\frac{3}{4}\ inches = \frac{7}{4}\ inches$

<em><u>What was the total snowfall for the three days?</u></em>

Total snowfall = first day + second day + third day

$Total\ snowfall = \frac{14}{4} + \frac{14}{4} + \frac{7}{4}\\\\Total\ snowfall = \frac{14 + 14 + 7}{4}\\\\Total\ snowfall = \frac{35}{4} \text{ or } 8.75\ inches$

Thus total snow fall for three days is 8.75 inches

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3 years ago

33. Suppose you were on a planet where the

tatyana61 [14]

<u>Answer:</u>

a) 3.675 m

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

3 years ago