Square root of 180 in radical form

Suppose you have already been waiting for one hour for a taxi. what is the probability that one arrives within the next 10 minut

Alona [7]

The probability of one arrives within the next 10 minutes when he already been waiting for one jour for a taxi is,

P (X > 70 | X > 60) = P (X > 10) = 1 – P (X ≤ 10) = 1 – {1 – e ^ -((1 / 10) 10)} = e ^ -1

= 0.3679

The probability of one arrives within the next 10 minutes when he already been waiting for one hour for a taxi is 0.3679

3 0

3 years ago

If a toaster oven that is connected to a 120 v plug has 16 A of current running through it, what is the resistance?

Alenkinab [10]

Answer:

The resistance is 7.5 ohms

Step-by-step explanation:

V = IR

V = voltage I is the current and R = resistance

120 = 16*R

Divide by 16 on both sides

120/16 = 16R/16

7.5 = R

The resistance is 7.5 ohms

4 0

3 years ago

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A line passes through the points (2,-4) and (6,10). What is the equation of the line?

deff fn [24]

Answer:

y = $\frac{7}{2}$ x - 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (2, - 4) and (x₂, y₂ ) = (6, 10)

m = $\frac{10+4}{6-2}$ = $\frac{14}{4}$ = $\frac{7}{2}$ , thus

y = $\frac{7}{2}$ x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, - 4) , then

- 4 = 7 + c ⇒ c = - 4 - 7 = - 11

y = $\frac{7}{2}$ x - 11 ← equation of line

7 0

2 years ago

Does (0,0) satisfy x+3y>3

PtichkaEL [24]

$\bf x+3y > 3\qquad \qquad (\stackrel{x}{0}~~,~~\stackrel{y}{0})\qquad \qquad 0+3(0) > 3\implies \stackrel{\stackrel{\textit{is this true?}}{\downarrow }}{0>3}\qquad nope!$

4 0

3 years ago

Of 560 marbles in a bag, 65% are red and the rest are blue. After 28 red marbles are replaced with blue ones, how many blue marb

jonny [76]

Answer: The answer is 400 blue marbles.

Step-by-step explanation: Given that there are 560 marbles in a bag, out of which 65% are red and rest are blue.

So, number of red marbles is

$n_r=65\%\times 560=\dfrac{65}{100}\times 560=364,$

and number of blue marbles is

$n_b=560-364=196.$

Now, if 28 red marbles are replaced by blue marbles, the the new number of red and blue marbles will be

$n_r^\prime=364-28=336~~~\textup{and}~~~n_b^\prime=196+28=224.$

Now, to get 65% of the marbles blue, we need to add some more blue marbles to the bag. Let 'x' number of blue marbles are added to the bag, then

$65\%\times (560+x)=224+x\\\\\Rightarrow \dfrac{65}{100}\times (560+x)=224+x\\\\\Rightarrow 13(560+x)=20(224+x)\\\\\Rightarrow 7280+13x=4480+20x\\\\\Rightarrow 7x=2800\\\\\Rightarrow x=400.$

Thus, 400 blue marbles need to be added to the bag.

5 0

3 years ago

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