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bonufazy [111]
3 years ago
9

A truck driver can travel 200 miles in 3 days. At that rate, how far will he travel in 12 days?

Mathematics
1 answer:
alexandr402 [8]3 years ago
8 0

Answer: the answer is 6000

Step-by-step explanation:

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PLEASE HELP! I HAVE TWO QUESTIONS AND WILL GIVE 100PTS AND BRAINLIEST IF CORRECT!
Volgvan

Answer:

1) $283.50

2) 65.21 meters.

Step-by-step explanation:

Part 1)

We know that a spool of ribbon holds 6.75 meters.

A craft club buys 21 spools.

So, the total length of ribbon bought is:

T=21(6.75)=141.75\text{ meters}

Each meter costs $2. So, the total cost will be:

141.75(2)=\$ 283.50

Part 2)

A spool holds 6.75 meters.

We bought 21 of them, so that total length we have is 141.75 meters.

The club used 76.54 meters.

So, the amount of ribbon that is left is represented by:

141.75-76.54

Subtract:

=65.21\text{ meters}

So, 65.21 meters of ribbon will be left.

7 0
3 years ago
Read 2 more answers
Craig opened a savings account and deposited $600.00 as principal. The account earns 2%
Solnce55 [7]

Answer:

the answer is 675.70 or 4,504.33

Step-by-step explanation:

the right answer is that

3 0
2 years ago
Find two unit vectors orthogonal to both given vectors. i j k, 4i k
Maurinko [17]
The cross product of two vectors gives a third vector \mathbf v that is orthogonal to the first two.

\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k

Normalize this vector by dividing it by its norm:

\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)

To get another vector orthogonal to the first two, you can just change the sign and use -\mathbf v.
6 0
3 years ago
Complete. Express the product in simplest form.<br><br> 2/5 of 7/10 =
tester [92]
Of means multiply in math (most of the time). 
So multiply. 
2/5 x 7/10 = 14/50 divided by 2/2 = 7/25 
3 0
3 years ago
Read 2 more answers
A driving exam consists of 30 ​multiple-choice questions. Each of the 30 answers is either right or wrong. Suppose the probabili
Butoxors [25]

Answer:

a. P(x>20)=0.19

b. P(x≥6)=0.72

c. P(x≤20)=0.81

d. A and C

Step-by-step explanation:

We know that:

1) the probability that a student makes fewer than 6 mistakes is 0.28

P(x

2) The probaiblity that a student makes between 6 to 20 mistakes is 0.53.

P(6\leq x\leq20)=0.53

We will express the proabilibities in function of the information we have.

a. Probability that a student makes more than 20 mistakes.

P(x>20)=1-P(x\leq20)=1-(P(x20)=1-(0.28+0.53)=1-0.81=0.19

b. Probability that the student make 6 or more mistakes

P(x\geq6)=1-P(Px

c. Probability that a student makes 20 mistakes at most

P(x\leq20)=P(x

d. A and C, because A takes a event of more than 20 mistakes and C takes the event of 20 or less mistakes. Both events cover a probability of 1.

7 0
3 years ago
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