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Maurinko [17]
3 years ago
12

please solve this and show your work, no links/ ip grabbers PLEASE i’ve been asking this forever i just need the answer

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
6 0
19x-15 = 15x -7
4x = 8
x =2
19(2) -15 = 23
15(2) -7 = 23
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is it possible to store a 20 foot long pipe in a rectangular room that is 10 feet by 12 feet by 8 feet?
Anastaziya [24]
First we'll consider the floor size.
In a 10 by 12 room the longest pipe that will fit lying on the floor equals the hypotenuse of a 10 by 12 triangle:
hypotenuse² = 10² + 12²
hypotenuse² = 100 + 144
hypotenuse² = 244
hypotenuse = <span> <span> <span> 15.62 feet

Now we have to consider the third dimension (height = 8 feet).
The two sides would be 15.62 and 8
</span></span></span>hypotenuse² = 15.62² + 8²
hypotenuse² = 244 + 64 = 308
hypotenuse = 17.55
So, the longest pipe that would fit in that room would be 17.55 feet long.


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4 years ago
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