2 1/2 divided by 4 3/4 as a fraction

Find the equation that has a slope of - 1/8 and passes through the point (0.-4)

nikdorinn [45]

Answer:

ez, answer choice number 4

Step-by-step explanation:

y=-1/8x(this is the slope) -4(this is the y intercept

4 0

2 years ago

Find the equation of the line through (6,4) and (-3,-8)

alexdok [17]

Answer:

y = 4/3x - 4

Step-by-step explanation:

to find the equation of a line with 2 points, we use the slope formula which is:

$\frac{y_2-y_1}{x_2-x_1}$

we will use (6,4) as $x_1[tex] and [tex]y_1$ and we will use (-3,-8) as $x_2[tex] and [tex]y_2$ . we plug this into the slope formula:

$\frac{-8-4}{-3-6}$

-8 - 4 = -12

-3 - 6 = -9

the slope is $\frac{-12}{-9}$

but we can simplify this further by dividing the fraction by -3

-12 / -3 = 4

-9 / -3 = 3

the simplified version of the slope is $\frac{4}{3}$

we can write this in slope-intercept form which is y =mx + b, with b being the y intercept and m being the slope

y = 4/3x + b <--- we need to solve for <em>b</em> in order to find the y intercept, so substitute x & y for a point on the line, we can use any point we are given, but for this example i will use (6,4)

4 = 4/3(6) + b < multiply 4/3 x 6

4 = 8 + b < subtract 8 from both sides

-4 = b

our y intercept would be (0,-4)

the equation looks like the following:

y = 4/3x - 4, which is our answer

3 0

2 years ago

Which shows the equation in point-slope form of the line passing through the given point with the given slope?

avanturin [10]

<h2>SOLVING</h2>

$\Large\maltese\underline{\textsf{A. What is Asked}}$

Find the point-slope equation of the line, with the info given

$\Large\maltese\underline{\textsf{This problem has been solved}}$

Formula used, $\bf y-y1=m(x-x1)$

$\bf y-5=13(x-0)}$ | result

$\rule{300}{1.7}$

$\boxed{\bf aesthetic\not101}}$

3 0

1 year ago

The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep

Alchen [17]

Ooh, fun

geometric sequences can be represented as
$a_n=a(r)^{n-1}$
so the first 3 terms are
$a_1=a$
$a_2=a(r)$
$a_2=a(r)^2$

the sum is -7/10
$\frac{-7}{10}=a+ar+ar^2$
and their product is -1/125
$\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3$

from the 2nd equation we can take the cube root of both sides to get
$\frac{-1}{5}=ar$
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
$\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r$
subsituting -1/5 for ar
$\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r$
which simplifies to
$\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}$
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for $ax^2+bx+c=0$
$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$
so
for 2r²-5r+2=0
a=2
b=-5
c=2

$r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}$
$r=\frac{5 \pm \sqrt{25-16}}{4}$
$r=\frac{5 \pm \sqrt{9}}{4}$
$r=\frac{5 \pm 3}{4}$
so
$r=\frac{5+3}{4}=\frac{8}{4}=2$ or $r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}$

use them to solve for the value of a
$\frac{-1}{5}=ar$
$\frac{-1}{5r}=a$
try for r=2 and 1/2
$a=\frac{-1}{10}$ or $a=\frac{-2}{5}$

test each
for a=-1/10 and r=2
a+ar+ar²= $\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}$
it works

for a=-2/5 and r=1/2
a+ar+ar²= $\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}$
it works

both have the same terms but one is simplified

the 3 numbers are $\frac{-2}{5}$ , $\frac{-1}{5}$ , and $\frac{-1}{10}$

6 0

3 years ago

Given the graph for function f(x) given above.Find the f (-2). f(-2) =

PIT_PIT [208]

Answer:

f(-2) = 3

Step-by-step explanation:

Look at the graph when x = -2, f(-2) = 3

5 0

2 years ago

Read 2 more answers